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slamgirl [31]
4 years ago
6

Which of the following properties did he use? Check all that apply

Mathematics
1 answer:
ad-work [718]4 years ago
3 0

What are all of your choices ?

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The domain of a function is the set of all negative numbers. Which quadrant could the function be located in? Select two that ap
Marina86 [1]

Answer:

Step-by-step explanation:

5 0
3 years ago
Estimate the product by rounding 3x5,186
masya89 [10]
The estimation of the product would be around 15,600 because if you round 5,186, it will become 5,200. multiply that by 3, and that's where you get your answer
3 0
3 years ago
Peggy is thinking of a number such that when twice the number is added to three times one more than the number she gets the same
mars1129 [50]

Answer:

-7

Step-by-step explanation:

Lets assume the number Peggy is thinking of be "x".

Now as given, when twice the number is added to three times one more than the number. We can write it as

∴ 2x+3(x+1)--- Equation 1

Again, it is given that Peggy gets the same result as when she multiplies four times one less than the number.

∴ 4(x-1)-- equation 2

Next, we can equate both the equation 1 and 2 as it is given that result is same.

2x+3(x+1)= 4(x-1)

Let´s distribute 3 into (x+1) and 4 into (x-1)

⇒ 2x+3x+3=4x-4

⇒ 5x+3=4x-4

Subtract both side by 4x and 3

∴ x=-7

∴ Peggy was thinking of -7

4 0
3 years ago
Mapnwea.org/glowest player
Lerok [7]

Answer:

It is B

Step-by-step explanation:

I hope this helps!

7 0
3 years ago
Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)
givi [52]

Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

Step-by-step explanation:

Since we have given that

y=x^{8sinx}

By using logarithmic on both sides we get,

log y= 8 sinx. logx

(∵ log(a^m)=m.loga)

Now, differentiating on both sides ,we get,

\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})

\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})

\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

6 0
3 years ago
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