3rd quartile is different, minimum is same, median is same, IQR is can't tell, mode is same,and mean is different
Complete the square:
F(x) = -3x² - 6x - 5
F(x) = -3 (x² + 2x) - 5
F(x) = -3 (x² + 2x + 1 - 1) - 5
F(x) = -3 ((x + 1)² - 1) - 5
F(x) = -3 (x + 1)² + 3 - 5
F(x) = -3 (x + 1)² - 2
The y-intercept has x-coordinate equal to 0, so it corresponds to the value of F(0) :
F(0) = -3 (0 + 1)² - 2 = -3 - 2 = -5
The axis of symmetry is the vertical line running through the vertex of this parabola, so we'll come back to this.
The vertex of the parabola is (-1, -2). This represents the maximum value of F(x), which follows from
(x + 1)² ≥ 0 ⇒ -3 (x + 1)² ≤ 0 ⇒ -3 (x + 1)² - 2 ≤ -2
This is to say, every point on the parabola has a y-coordinate no greater than -2.
As mentioned earlier, the axis of symmetry is the vertical line through the vertex, and its equation is determined by the x-coordinate of the vertex. Hence the AoS is the line x = -1.
Answer:
in 203060708030506040 hours there are 203060708030506040×60 seconds
Assign variables to you unknowns.
c = $ cars
t = $ trucks
6c + 3t = 4800
8c + t = 4600
use substitution or elimination to solve the system of equations.
using elimination.. multiply second equation by -3 and add to the other to combine equations into one.
6c + 3t = 4800
-3(8c + t = 4600)
---------------------------
-18c + 0 = -9000
c = 9000/18
c = 500 $
use this in one of the equations to find the cost of a truck.
8(500) + t = 4600
4000 + t = 4600
t = 4600 - 4000
t = 600 $
question asks
2(500) + 3(600) =
1000 + 1800 = 2800 $
