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4 years ago

(4g^3-1) (3g-10) and show work please

1 answer:

5 0

Hello! And thank you for your question!

For this problem we can use the FOIL method/distributive method.

Rewrite the equation to:

(4g³) + (-1)(3g) + (-10)

Then solve:

(4g³) times (3g¹) = 12g⁴

(4g³) times (-10) = -40g³

(-1) times (3g) = -3g

(-1) times (-10) = 10

Final Answer:

12g⁴ - 40g³ - 3g + 10

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2 years ago

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3 years ago

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Your answer for part A is P = 2w + 2L

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They tell us in part b, that:
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Substitute that into what we got for part a.

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Your answer for partb is P = 14L + 40

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So we take what we got from part b, and solve for L.

P = 14L + 40
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$L = \boxed{\frac{P-40}{14}}$

That is your answer for part 3 ^

part d.

Plug in w = 32 into what we first got in part b.

w = 6L + 20
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Your answer for part d is L = 2

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Step-by-step explanation:

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