1/2 because 6/7 and 6/5 are over 1 and 3/4 is greater than 1/2
Answer:
2√37
Step-by-step explanation:
Given some complex number z, |z| is what's called <em>magnitude </em>of a complex number -- its distance from 0. Unlike the more straightforward process of finding the absolute value of a real number (a number on the number line) complex numbers are <em>two-dimensional</em>, and so to talk about their magnitude, we need to bring in the Pythagorean theorem.
The real and imaginary part of the complex number 12 - 2i represent the point (12, -2) on the complex plane. Drawing lines perpendicular to the real and imaginary axes and joining them with a line from the origin to the point gives us a right triangle with legs 12 and 2. Using the Pythagorean theorem, the hypotenuse, |12 - 2i|, must be equal to
. We can pull a 4 out of the 148 to give us
![\sqrt{4\cdot37}=\sqrt{4}\sqrt{37}=2\sqrt{37}](https://tex.z-dn.net/?f=%5Csqrt%7B4%5Ccdot37%7D%3D%5Csqrt%7B4%7D%5Csqrt%7B37%7D%3D2%5Csqrt%7B37%7D)
Answer:
==================== not < or >
Step-by-step explanation:
kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
e
e
e
e
e
e
e
e
e
e
e
e
e
e
e
e
e
hehe, the explanation is down here xD
m=3
4m-1=4*3-1
so then it's 12-1 which is 11
5m-4=5*3-4
15-4 thats 11
wait ok so
11=11
We conclude that the coordinates that describe the location of point P' are (4, -2).
<h3>
What ordered pair describes the location of P'?</h3>
For a random point with coordinates (x, y), a reflection over the x-axis only changes the sign of the y-component. So the coordinates after the reflection are (x, -y).
In this case, the coordinates of point P are (4, 2), so if we apply a reflection over the x-axis to get the point P', the coordinates are:
(4, -2)
Where we just changed the sign of the y-component.
We conclude that the coordinates that describe the location of point P' are (4, -2).
If you want to learn more about rotations.
brainly.com/question/4289712
#SPJ1
Answer:
$61
Step-by-step explanation:
Given
Number of days, x = 5
Expenditure per day, E'(x) = 10x + 11
Required
Determine the expenditure per day (E'(x))
From the question, we have that
![E'(x) = 10x + 11](https://tex.z-dn.net/?f=E%27%28x%29%20%3D%2010x%20%2B%2011)
Substitute 5 for x
![E'(5) = 10 * 5 + 11](https://tex.z-dn.net/?f=E%27%285%29%20%3D%2010%20%2A%205%20%2B%2011)
![E'(5) = 50 + 11](https://tex.z-dn.net/?f=E%27%285%29%20%3D%2050%20%2B%2011)
![E'(5) = 61](https://tex.z-dn.net/?f=E%27%285%29%20%3D%2061)
Hence, the expenditure for 5 days is $61