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vfiekz [6]
3 years ago
8

16) A company has found that its expenditure rate per day (in hundreds of dollars) on a certain type of job is given by E'(x) =

10x + 11, where x is the number of days since the start of the job. Find the expenditure if the job takes 5 days. A) $61 B) $6100 C) $180 D) $18,000
Mathematics
1 answer:
erastova [34]3 years ago
3 0

Answer:

$61

Step-by-step explanation:

Given

Number of days, x = 5

Expenditure per day, E'(x) = 10x + 11

Required

Determine the expenditure per day (E'(x))

From the question, we have that

E'(x) = 10x + 11

Substitute 5 for x

E'(5) = 10 * 5 + 11

E'(5) = 50 + 11

E'(5) = 61

Hence, the expenditure for 5 days is $61

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Two companies, A and B, drill wells in a rural area. Company A charges a flat fee of 3681 dollars to drill a well regardless of
jekas [21]

Answer:

Mean costing =  $3,768

Step-by-step explanation:

Given:

Mean A(x) = 260

Rate = $10 per feet

Fixed charge = $1,168

Computation:

Assume;

depth = x ft

So,

Cost of company B = 10x + 1,168

So,

Mean costing = 10A(x) + 1,168

Mean costing =  10(260) + 1,168

Mean costing =  2,600 + 1,168

Mean costing =  $3,768

3 0
3 years ago
Find the area of the figure <br><br> Please help :)
ASHA 777 [7]

9514 1404 393

Answer:

  372 m²

Step-by-step explanation:

A vertical line down the center of the figure will divide it into two congruent trapezoids, each with bases 13 and 18, and height 12.

The area of one of them is ...

  A = 1/2(b1 +b2)h

So, the area of the two of them together is ...

  A = (2)(1/2)(b1 +b2)h = (b1 +b2)h

  A = (13 m + 18 m)(12 m) = 372 m²

6 0
3 years ago
There are 1200 balls in a ball pit. 35.5% of them are green. How many green balls are there?
anyanavicka [17]

Answer:

426

Step-by-step explanation:

35.5% of 1200 is 426

3 0
3 years ago
The heights of 20-year-old females are normally distributed with a mean of 64 inches 
Oduvanchick [21]

Answer:

1.5

Step-by-step explanation:

Applying,

Z = (x-μ)/σ................. Equation 1

Where Z = Z score for a height of 67 inches, x = height, μ = mean of the height, σ = standard deviation of the height.

From the question,

Given: x = 67 inches, μ = 64 inches, σ = 2 inches.

Substitute these values into equation 1

Z = (67-64)/2

Z = 3/2

Z = 1.5

6 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
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