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3 years ago

The segments shown below could form a triangle. 15 A O A. True B. False

Mathematics

2 answers:

netineya [11]3 years ago

7 0

Answer:

false

Step-by-step explanation:

Because every segment must be minor than the sum of the other two

Morgarella [4.7K]3 years ago

5 0

Answer:

False

Step-by-step explanation:

9 + 4 must be > 15

9+4 is < than 15

False

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Answer this question pls!! (Will give Brainliest)

aev [14]

Answer:

first blank is 90/100

second blank is 145/100

Step-by-step explanation:

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3 years ago

A data set of with whole numbers has a low of 20 and a high value of 89

Vikentia [17]

Answer:

The range is 69

Step-by-step explanation:

We have that the least value of the data set is 20 and the highest value is 89.

From the available information, we can only find the range of the data set.

The range is the highest value minus the least value.

This implies that, the range is $89-20=69$

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3 years ago

-y-4=4x<br> put in y=mx+b

marishachu [46]

$-y-4=4x\\ \\ -y=4x+4\\ \\ y=-4x-4$

<h3>First part of the problem:</h3><h3>-y - 4 = 4x</h3><h3> + 4 + 4</h3><h3>-y + 0 = 4x + 4</h3><h3> -y = 4x + 4</h3><h3 />

Hope this helps!

3 0

3 years ago

I will give brainiest to whoever answers correctly !!

pogonyaev

I don’t know if this is the right answer

700*.075 ÷ 24 will give you your monthly payment.

Explanation: brainly.com/question/9271155

8 0

2 years ago

If (5x− 4)(3x+ 7) = 15x²-ax-b,then find the value of a and b

Mkey [24]

Answer:

$a=-23\\\\b=28$

Step-by-step explanation:

Let's start by using distributive multiplication:

$(a\pm b)(c\pm d)=ac\pm ad \pm bc \pm bd$

So:

$(5x-4)(3x+7)=15x^2+35x-12x-28\\\\$

Grouping like terms:

$15x^2 +(35x-12x)-28\\\\15x^2+23x-28$

Now, $15x^2+23x-28$ is equal to:

$15x^2-ax-b$

In this sense:

$15x^2+23x-28=15x^2-ax-b$

In order to satisfied the equality:

$23x=-ax\hspace{10}(1)\\\\and\\\\-28=-b\hspace{10}(2)$

Hence, from (1), let's solve for a:

$23x=-ax\\\\-a=\frac{23x}{x} \\\\-a=23\\\\a=-23$

And from (2), let's solve for b:

$-28=-b\\\\b=28$

Let's verify the result evaluating the values of a and b into the original equation:

$(5x-4)(3x+7)=15x^2+23x-28=15x^2 -ax -b\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 -(-23)x -(28)\\\\(5x-4)(3x+7)=15x^2+23x-28=15x^2 +23x -28$

As you can see, the values satisfy the equation, therefore, we can conclude they are correct.

3 0

3 years ago