All categories

3 years ago

Find the length of UW if W is between U and V, UV = 25.1 and VW = 13.9

Mathematics

1 answer:

marysya [2.9K]3 years ago

5 0

Answer:

The length of UW is 11.2

Step-by-step explanation:

Here, we are told to find the length of UW given the lengths in the question;

We are told that w is between U and V

Thus;

U W 13.9 V

While the total length UV is 25.1

Mathematically;

UV = VW + UW

Thus;

UW = UV - VW

So UW = 25.1 - 13.9 = 11.2

You might be interested in

Extended rotation rules

Westkost [7]

Ehjaklopiuftdhsabmzcbs

8 0

3 years ago

Read 2 more answers

URGENT!!! anyone know this? 10 POINTS!

stiks02 [169]

I tried my best at it and my guess is that in standard form is 0.00086

5 0

3 years ago

Please answer with proof/work I give points

Phoenix [80]

Answer:

H. 8.874 hours

Step-by-step explanation:

There is a seven, that has the value of 7/100. 7/100 as a decimal is .07 because there is a 7 in the hundredths place. There has to be a number that contains 7/100, or a value in the hundredths place, and that is 8.874.

Hope this helps!

3 0

3 years ago

Read 2 more answers

If 3x - 2 (4x - 8) = 16 , then x = 0.<br> True<br> False

Andrew [12]

Answer:

try your best

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago