Answer:
B The cost, in dollars, for each additional gigabyte used.
Step-by-step explanation:
C = 59 + 15(g − 5)
when g=5, C=59 where it is the monthly cost
when g=6, c=59 +15, interpret that each additional gigabyte used will increase the cost for 15
a. Write and graph an equation in two variables that represents the total cost of ordering the shirts.
For this case, the first thing we must do is define variables:
c = total cost
x = x number of shirts.
The equation that adapts to the problem is:
c (x) = 10x + 20
Answer:
c (x) = 10x + 20
b. Choose an ordered pair that lies on your graph in part (a). Interpret it in the context of the problem.
Let's choose the next ordered pair:
(x, c (x)) = (0, 20)
We verify that it is in the graph:
c (20) = 10 (0) + 20
c (20) = 20 (yes, it belongs to the graph).
In the context of the problem, this point means that the cost per shipment is $ 20
Answer:
(0, 20)
Cost per shipment is $ 20
There are 2 options to solve that.
1. The first one is by derivatives.
f(x)=x^2+12x+36
f'(x)=2x+12
then you solve that for f'(x)=0
0=2x+12
x=(-6)
you have x so for (-6) solve the first equation, then you find y
y=(-6)^2+12*(-6)+36=(-72)
so the vertex is (-6, -72)
2. The second option is to solve that by equations:
for x we have:
x=(-b)/2a
for that task we have
b=12
a=1
x=(-12)/2=(-6)
you have x so put x into the main equation
y=(-6)^2+12*(-6)+36=(-72)
and we have the same solution: vertex is (-6, -72)
For next task, I will use the second option:
y=x^2-6x
x=(-b)/2a
for that task we have
b=(-6)
a=1
x=(6)/2=3
you have x so put x into the main equation
y=3^2+(-6)*3=(--9)
and we have the same solution: vertex is (3, -9)
Answer:
the answers are
a) Area of triangle is 15 square inches
Perimeter of triangle is 18.5 inches.
b) Area of trapezium is 210 square cm.
Perimeter of trapezium is 61.5 cm.
c) Area of parallelogram is 21 square yards
perimeter of parallelogram is 22 yards
Step-by-step explanation:
Area of triangle is 1/2( base × height)
Area of trapezium is 1/2(p1 + p2)×height
Area of parallelogram is base × height