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eduard
3 years ago
7

A soccer team will sell T-shirts for a fundraiser. The company that makes the T-shirts charges $10 per shirt plus a $20 shipping

fee per order.
a. Write and graph an equation in two variables that represents the total cost of ordering the shirts.
b. Choose an ordered pair that lies on your graph in part (a). Interpret it in the context of the problem.
(im the worst in math)
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
3 0
a. Write and graph an equation in two variables that represents the total cost of ordering the shirts.
 For this case, the first thing we must do is define variables:
 c = total cost
 x = x number of shirts.
 The equation that adapts to the problem is:
 c (x) = 10x + 20
 Answer:
 c (x) = 10x + 20

 b. Choose an ordered pair that lies on your graph in part (a). Interpret it in the context of the problem.
 
Let's choose the next ordered pair:
 (x, c (x)) = (0, 20)
 We verify that it is in the graph:
 c (20) = 10 (0) + 20
 c (20) = 20 (yes, it belongs to the graph).
 In the context of the problem, this point means that the cost per shipment is $ 20
 Answer:
 (0, 20)
 Cost per shipment is $ 20
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Answer:

The p-value of the test is of 0.1922 > 0.02, which means that there is not significant evidence to reject the null hypothesis, that is, there is not significant evidence to conclude that the proportion is of less than 40%.

Step-by-step explanation:

Test if the proportion is less than 40%:

At the null hypothesis, we test if the proportion is of at least 0.4, that is:

H_0: p \geq 0.4

At the alternative hypothesis, we test if the proportion is of less than 0.4, that is:

H_1: p < 0.4

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

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0.4 is tested at the null hypothesis:

This means that \mu = 0.4, \sigma = \sqrt{0.4*0.6}

74 out of the 200 workers sampled said they would return to work

This means that n = 200, X = \frac{74}{200} = 0.37

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.37 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}

z = -0.87

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.37, which is the p-value of z = -0.87.

Looking at the z-table, z = -0.87 has a p-value of 0.1922.

The p-value of the test is of 0.1922 > 0.02, which means that there is not significant evidence to reject the null hypothesis, that is, there is not significant evidence to conclude that the proportion is of less than 40%.

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Step-by-step explanation:

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