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Vikentia [17]
3 years ago
12

logan swam 750 meters in 1/3 hour mila swam 3/3 of logans distance in 1/4 hour what is logans average swimming speed? what is mi

las swimming speed? show work
Mathematics
1 answer:
user100 [1]3 years ago
3 0

Answer:

Logan's average swimming speed = 0.625 metres/second

Mia's  average swimming speed0.833 metres/second

Step-by-step explanation:

Speed is obtained by dividing the distance covered by the time taken to cover such a distance.

<em>It will be necessary to make sure we are working in seconds for our time units.</em>

Logan's swimming time: 1/3 hours will be = 20 minutes = 1200 seconds

Mia's swimming time: 1/4 hours will be = 15 minutes = 900 seconds

Logan swam 750 metres. Logan's swimming speed will be

750metres / 1200 seconds = 0.625 metres/second

Mia's distance swam is 3/3 of Logan's. If we reduce the fraction 3/3 to its lowest term, we will have that it will be = 1/1.

1/1 X 750metres = 750 metres.

This means that Mia swam exactly the same distance as Logan.

Mia's swimming speed = 750 metres/ 900 seconds = 0.833 metres/second

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Step-by-step explanation:

Let

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Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

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Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

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Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

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Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$15=100\%$.

Step 4: Similarly, $x=60\%$.

Step 5: This results in a pair of simple equations:

$15=100\%(1)$.

$x=60\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{15}{x}=\frac{100\%}{60\%}$

Step 7: Again, the reciprocal of both sides gives

$\frac{x}{15}=\frac{60}{100}$

$\Rightarrow x=9$

Therefore, $60\%$ of $15$ is $9$

Step-by-step explanation:

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