Answer:
0.1319 or 13.2%
Step-by-step explanation:
You can solve this using the binomial probability formula.
The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.
Then, we can set the equation as follows:
P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k)
n=4, x=2, k=2
when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157
when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154
when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008
Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)
Answer:
No solution
Step-by-step explanation:
In pic
<u><em>(Credits: Symbolab) </em></u>
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(Hope this helps can I pls have brainlist (crown)☺️)
Answer:
where is the hint
Step-by-step explanation:
you might want to try reading the hint
Answer:
≈85.43
Step-by-step explanation:
apply the binomial theorem to the square
≈85.43
Hope this helps
