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3 years ago

Is 23/48 less than 1/2

Mathematics

2 answers:

Marrrta [24]3 years ago

5 0

Answer:

yes.

Step-by-step explanation:

24/48 is half. Anything less than 24 would be less than half.

Alecsey [184]3 years ago

5 0

Answer:

Yes.

Step-by-step explanation:

Half of 2 is 1, so 1/2 means half.

Half of 48 is 24, so 24/48 is also half.

23/48 is less than 24/48, so 23/48 is less than 1/2.

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18. During a clothing store's Bargain Days, the regular price for T-shirts is discounted to $8.25.

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Answer:

3.25

Step-by-step explanation:

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2 years ago

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The function A=A_oe^{-0.01155x} A = A o e − 0.01155 x models the amount in pounds of a particular radioactive material stored in

vivado [14]

They are essentially asking us to solve:

$357=900e^{-0.01155x} \implies\\ \frac{357}{900}=e^{-0.01155x} \implies\\ \ln{\frac{357}{900}}=-0.01155x \implies \\ x\approx 80.1$

Solving this equation for x tells us that it will take around 80.1 years for the materials in the vault to reduce to 357 pounds.

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3 years ago

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Solve the following equation for X. Round your answer to four decimal places.

strojnjashka [21]

ANSWER

x = 1.2226

EXPLANATION

To solve this equation we have to apply the property of the logarithm of the base,

$\log _bb=1$

Thus, we can apply the natural logarithm - whose base is e, to both sides of the equation,

$\ln e^{4x}=\ln 133$

Now we apply the property of the logarithm of a power,

$\log a^b=b\log a$

In our equation,

$\begin{gathered} 4x\ln e^{}=\ln 133 \\ 4x^{}=\ln 133 \end{gathered}$

Then divide both sides by 4 and solve,

$\begin{gathered} \frac{4x^{}}{4}=\frac{\ln 133}{4} \\ x\approx1.2226 \end{gathered}$

The solution to this equation is x = 1.2226, rounded to four decimal places.

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1 year ago

The high temperature was 92 degrees. This was 24 degrees higher than the overnight low temperature. Write an equation to determi

Romashka-Z-Leto [24]

L = H - 24
L = low temperature.
H = High Temperature = 92 degrees
L = 92 - 24
L = 68

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3 years ago

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Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

4vir4ik [10]

Using the z-distribution, it is found that since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is tested if the mean length of jail time is still of 2.5 years, that is:

$H_0: \mu = 2.5$

At the alternative hypothesis, it is tested if it has increased, that is:

$H_1: \mu > 2.5$

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}$

$z = 1.7$

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.05, is of $z^{\ast} = 1.645$

Since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.

A similar problem is given at brainly.com/question/24166849

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2 years ago