Question

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a rate of 90 miles per hour. Train B leaves Milford at 8:00 a.M. And travels at 70 miles per hour. Which train(s) will arrive in Pinkerton before 1:00 p.M.?

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

For train A:

Distance from Milford and Pinkerton is 300miles.

Speed of train A is 90 miles per hour.

So, time taken to complete this distance = $\frac{distance}{speed}$

So, time taken to complete this distance =$\frac{300}{90}=3.333$

Means train A will take 3.33 hours or say 3 hrs and 19.8 minutes to reach Pinkerton.

So,if it starts at 10:00 AM, then it will reach at 01 hrs 19.8 minutes PM (01:19.8 PM).

For train B:

Speed of train B is 70 miles per hour.

Train B will take time =$\frac{300}{70}=4.29$

Means 4 hrs and 17.4 minutes.

So, if it starts at 8:00 Am, then it will reach at 12 hrs 17.4 minutes PM(12:17.4 PM).

So, train B will be reaching Pinkerton before 1:00 PM   :  Answer

Hope it will help :)