Answer:
(-5,7) (-5,8) (-5,3)
Step-by-step explanation:
Dont know if this will help but here you go
Answer:
![r=\frac{41}{14}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B41%7D%7B14%7D)
Step-by-step explanation:
![\frac{3r-2}{5} =\frac{5+2r}{8} \\\\8(3r-2)=5(5+2r)\\24r-16=25+10r\\24r-10r=25+16\\14r=41\\\\r=\frac{41}{14}](https://tex.z-dn.net/?f=%5Cfrac%7B3r-2%7D%7B5%7D%20%3D%5Cfrac%7B5%2B2r%7D%7B8%7D%20%5C%5C%5C%5C8%283r-2%29%3D5%285%2B2r%29%5C%5C24r-16%3D25%2B10r%5C%5C24r-10r%3D25%2B16%5C%5C14r%3D41%5C%5C%5C%5Cr%3D%5Cfrac%7B41%7D%7B14%7D)
Answer:
d
Step-by-step explanation:
Answer:
Step-by-step explanation:
Since the coefficient of x^2 is positive, this quadratic is a parabola in the shape of a U, hence has a minimum.
We want to end up with the form (x-h)^2 + c. Since (x-h)^2>=0, this form shows that the minimum is achieved when x=h.
Completing the square will put the quadratic in the desired form. Note that:
(x-h)^2=x^2-2hx+h^2
Comparing this with the given form, we must have -8=-2h, or h=4. But we are missing h^2=4^2=16. We can add the missing 16 and subtract it elsewhere without changing the quadratic.
x^2-8x+16 + (16-4) = (x-4)^2 + 12
Now we know that at x=4 the quadratic has a minimum and that the minimum is 12.
Answer:The short answer would be y=2x+4
Step-by-step explanation:
Here's why standard form is y=mx+b.
Thus, if we solved 2x-y=-4, we would get y+2x+4.
1. 2x-y=-4
2. -y= -2x-4
3. y=2x+4