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levacccp [35]
3 years ago
15

Find the interquartile range and range of 125,17,23,16,21,18,16,15,11,35,18,24,18,3

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0
Interquartile Range = 7.5
Range = 122
Marat540 [252]3 years ago
3 0

range = highest value - lowest value = answer

Range: 125 - 3 = 122

Interquartile Range: upper quartile - lower quartile = answer

Interquartile range: 23 - 16 = 7

lower quartile = 16

upper quartile = 23

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Answer:

z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29  

Step-by-step explanation:

information given

\bar X=10.6 represent the sample mean  

\sigma=4.1 represent the population standard deviation

n=45 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value for the test

Hypothesis to test

We want to test if the true mean is less than 12, the system of hypothesis would be:  

Null hypothesis:\mu \geq 10  

Alternative hypothesis:\mu < 10  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

Replacing the info given we got:

We can replace in formula (1) the info given like this:  

z=\frac{10.6-12}{\frac{4.1}{\sqrt{45}}}=-2.29  

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<span>D. 7/8 

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pychu [463]

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Paraphin [41]

Answer:

Center: (-1,8)

Radius: 1

The graph is attached.

Step-by-step explanation:

The equation of the circle has the form:

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Where (h,k) is the  point of the center of the circle and r is the radius of the circle.

The equation given in the problem is

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You can graph the circle with its center at the (-1,8) and a radius of 1 as you can see in the figure attached.

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3 years ago
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