Ask question

Ask question

All categories

3 years ago

5

It takes one examiner 36 hours to mark 70 exam papers. How long would it take 6 examiners to mark 70 papers?

1 answer:

Orlov [11]3 years ago

3 0

Answer:

36 divided by 6 is 6

Step-by-step explanation:

idk if im right i j wokeup lol

You might be interested in

Help please and thanks! I'll award brainliest if you show your work as well :)

iren2701 [21]

Answer:

6 inches

Step-by-step explanation:

Formula for surface area of a cylinder:

$SA=2\pi r^{2} +2\pi rh$

Plug in values and solve for the radius:

$180\pi =2\pi r^{2} +2\pi r(9)\\$

Divide both sides by $2\pi$

$90=r^{2} +r(9)$

Subtract 90 from both sides

$0=r^{2} +9r-90$

Use the quadratic equation to find the roots

$x=(-b$ ± $\sqrt{b^2-4ac})*\frac{1}{2a}$ (sorry for formatting, Brainly doesn't

allow equations with ± in them)

$x=\frac{-9+\sqrt{9^2-4*1*90} }{2(1)}$ and $x=\frac{-9-\sqrt{9^2-4*1*90} }{2(1)}$

$x=\frac{(-9+\sqrt{81+360})}{2}$ and $x=\frac{(-9-\sqrt{81+360})}{2}$

$x=\frac{(-9+\sqrt{441})}{2}$ and $x=\frac{(-9-\sqrt{441})}{2}$

$x=\frac{(-9+21)}{2}$ and $x=\frac{(-9-21)}{2}$

$x=\frac{12}{2}$ and $x=\frac{-30}{2}$

$x=6$ and $x=-15$

We can't have a negative radius, so that leaves us with r=6 in.

8 0

2 years ago

Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in

Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907$

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

$\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}$

$\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45$

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0

2 years ago

I need help quick I can’t fail I need a good grade pls help

dusya [7]

B I think I am unsure

5 0

3 years ago

Read 2 more answers

2 1/2 + 3<br> As a fraction or a mixed number in simplest form. please Thankss ;p

puteri [66]

5 1/2 i think is the answer

5 0

3 years ago

Read 2 more answers

Two hundred copies can be made for $6.00.<br>What is the unit rate?

Mekhanik [1.2K]

Answer:

.03 cents

Step-by-step explanation:

6 divided by 200 equals 0.03

5 0

3 years ago

Read 2 more answers