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soldi70 [24.7K]
3 years ago
6

PLS HELP!

Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer:The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = 2x2 + x − 3 and g(x) = x − 1. Find f(x) • g(x). The domain for f(​x) ...

1 answer

·

Top answer:

Just multiply the two functions. You can usea a variety of ways. I like t

Step-by-step explanation:

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they won 85.7%

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Simplify 8x^4/x^3+7x^4 and Find the excluded values​
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So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.

Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4

So then we get 8x^4/(x^(3/4)+7x)^4

8x^4/(x^(3/4)+7x)^4

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An object travels 60 miles in 1/2 hour. How many miles does the object<br> travel in 6 hours
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A rock is thrown upward from a bridge that is 57 feet above a road. The rock reaches its maximum height above the road 0.76 seco
bekas [8.4K]

answer:

f(t) = -9.9788169(t -0.76)^2 +57

Step-by-step explanation:

On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the  number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).

now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is f(x)= a(x-p)^2 +q  , where (p,q) is the turning point. now we substitute the turning point

f(t) = a(t-0.76)^2 + 57, now we will substitute the other point on the graph or on the function that we found which is (3.15, 0) then solve for a.

0 = a(3.15 - 0.76)^2 + 57

-57 =a(2.39)^2  

-57 = a(5.7121)

-57/5.7121 =a

-9.9788169 = a      then we substitute a to get the quadratic equation therefore f is

f(t) = -9.9788169(t-0.76)^2 +57

4 0
2 years ago
Use the quadratic formula to solve for x.
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0.64,-3.14 I’m not really sure about the -3.14. (Sorry).
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