Answer:
x= (y-5)/2
Step-by-step explanation:
Isolate the x variable.
y= 2x +5
Subtract 5 from both sides.
y-5=2x
Divide both sides by 2.
(y-5)/2= x
Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
Answer:
b = -2 2/3
Step-by-step explanation:
Isolate the variable, b. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 5 from both sides:
-3b + 5 (-5) = 13 (-5)
-3b = 13 - 5
-3b = 8
Next, divide -3 from both sides:
(-3b)/-3 = (8)/-3
b = -8/3
b = -2 2/3
~
Answer:
I think its 45
Step-by-step explanation:
Answer:
AB = 1.33
Step-by-step explanation:
AB and QR are in a ratio of 3 to 8 so we can create this proportion:
(3x+5)/24 = 3/8
cross-multiply:
8(3x+5) = 72
divide each side by 8 to get:
3x + 5 = 9
3x = 4
x = 4/3 or 1.33 repeating
