Answer:
The population will reach 34,200 in February of 2146.
Step-by-step explanation:
Population in t years after 2012 is given by:
In what month and year will the population reach 34,200?
We have to find t for which P(t) = 34200. So
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this question:
So 
Then
We only take the positive value.
134 years after 2012.
.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.
So the population will reach 34,200 in February of 2146.
Answer:
Angle: 22.5 deg, Complement: 67.5 deg, Supplement: 157.5 deg
Step-by-step explanation:
22.5 is 1/3 of 67.5
so compliment is 67.5.
Supplement is just adding another angle so I chose 7.
I did 22.5 x 7 = 157.5
Another example would be:
Angle: 10 deg, Complement: 30 (because 10 x 3), Supplement: 70 (because 10 x 7)
Hope this helps :)
Answer:
(4,1)
Step-by-step explanation:
Multiply the two values together to get 45 * 3/5 = 135/5 = 27
We know that
the equation of a sphere is
(x-h)²+(y-k)²+(z-l)²=r²
where (h,k,l) is the center and r is the radius
we have
x²+y²+z²<span>−2x−4y+8z+17=0
</span>
Group terms that contain the same variable, and move the
constant to the opposite side of the equation
(x²+2x)+(y²-4y)+(z²+8z)=-17
<span>Complete
the square. Remember to balance the equation by adding the same constants
to each side
</span>(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=-17+1+4+16
(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=4
Rewrite as perfect squares
(x+1)²+(y-2²)+(z+4)²=4
(x+1)²+(y-2²)+(z+4)²=2²
the center is the point (-1,2,-4) and the radius is 2 units
