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ziro4ka [17]
2 years ago
8

What is the answer to Y=-2x+3???????????????????????

Mathematics
1 answer:
Natali [406]2 years ago
3 0
I think is -2 or (0,3)

X | Y
0 | 3
1 | 1
You might be interested in
Which number completes this Pythagorean triple 300, 400 ?
forsale [732]
300²+400²=500² is your answer
a²<span> + b</span>²<span> = c</span>²
8 0
2 years ago
Show Work<br><br> Find the slope (5,-3), (-7,0)
Alex777 [14]
You'd use the equation y2-y1/x2-x1

0-(-3)/-7-5 = 3/-12 = -1/4

So -1/4 would be the slope
m= -1/4
4 0
3 years ago
WILL GIVE BRAINLIEST The angle of elevation from Ben to the top of a telephone pole is 62 degrees. If Ben is standing 8 feet fro
MrRissso [65]

Answer: The height of the telephone pole = $15.046

Step-by-step explanation:

Given: Angle of elevation= 62 degrees.

Distance of Ben from the base of the pole = 8 feet

According to trigonometry, we have

\tan x=\dfrac{\text{side opposite to x}}{\text{side adjacent to x}}

i.e.

\tan 62^{\circ}=\dfrac{\text{ height of the telephone pole}}{8}\\\\(1.880726)=\dfrac{\text{ height of the telephone pole}}{8}\\\\\text{ Height of the telephone pole} = 8\times 1.880726\approx15.046

Hence, The height of the telephone pole = $15.046

4 0
2 years ago
Given that P = x + y . Find P when: x = 20 and y = − 24 P = ?
mr_godi [17]

Answer:

P = -4

Step-by-step explanation:

Assuming that x = 20 and y = 24, you have to plug in these numbers for x and y to get to this equation P = 20 - 24.  You should get -4 when you subtract 24 from 20 giving you a negative answer.

6 0
3 years ago
A local swim club offers competitive meets throughout the season. Some races are open competitions with no qualifying times. Oth
sammy [17]

Answer:

The first option is correct.

The group competing in the open competitions is most likely to have a higher standard deviation than the group competing in the qualified competitions.

Step-by-step explanation:

The standard deviation of a dataset measures how the dataset spreads round a particular average value.

For the qualified competitions, there's a standing rule that only 15-16 year olds that post swimming times of 1 minute 8 seconds or less in the 100 m swimming race can participate in this competition. This means, all the participants of this particular competition are good swimmers relatively and the spread of their resulting swimming times should be just around the 1 minute and 8 second. If there will be outliers, it'll be a very few one.

Therefore, the standard deviation of their swimming times will not be so large as all the data focuses around 1 minute and 8 seconds.

But in the open competition, everyone can participate. It is open to skilled, unskilled, fast, slow, shy, brave, basically all types of swimmers. And with this diverse talent pool comes the large variation in swimming times. Plenty unskilled and slow people will post swimming times that are way more than 1 minute & 8 seconds, some few good ones will post numbers that are good enough and close to 1 minute, 8 seconds. At the end of the day, the large variation in swimming times across the talent spectrum leads to a large standard deviation.

So, the group competing in the open competitions is most likely to have a higher standard deviation than the group competing in the qualified competitions.

Only if not too many people participate in eirher of the competitions can this reasoning be faulty.

8 0
3 years ago
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