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yawa3891 [41]
3 years ago
7

The device used to connect a network to the internet is called a

Computers and Technology
1 answer:
melamori03 [73]3 years ago
8 0
That's called a router. you can hook up several computers to a router
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Dedicated server hosting and dedicated web dedicated is the same ??????
andrezito [222]

The correct answer is; False.

Further Explanation:

Dedicated server hosting and a dedicated shared hosting is two different things. When a person is using dedicated server hosting they are using a server that only hosts their website. When a person is using a dedicated shared host they are actually sharing the site with others. When using the shared server they must use only an allocated amount of space and bandwidth.

The costs of these services will vary depending on which you use. Shared servers will pay less for the website since they share the costs with the other site owners. While, a dedicated server will cost more since there is no one to share the cost with.

Learn more about server hosting at brainly.com/question/8429135

#LearnwithBrainly

3 0
3 years ago
QUESTIONS Which of the following use cases are suitable for compute-optimized cloud offering? ОА. None of the listed O B. Highly
Ede4ka [16]

Answer:

E. All of the listed ​

Explanation:

For compute-optimized cloud offerings like AWS, suitable use cases are - gaming, distributed analytics, and scientific modeling. Since all these are suitable, the correct answer is E.

4 0
3 years ago
A 4-bit left shift register is initially in the 0000 state, with all the flip flops storing 0s. A group of bits 1011 is serially
frutty [35]

Answer:

0010

Explanation:

Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:

Initial State of the Register:

0000

Group of bits entering:

1011

<u>First Clock Cycle:</u>

0000 <em>(This bold bit will move out)</em>

1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>

The resulting Sequence:

0001

<u>Second Clock Cycle:</u>

0001 <em>(This bold bit will move out)</em>

1011 <em>(This bold bit will move in from right side, shifting the whole sequence one place to the left).</em>

The resulting Sequence:

0010 <em>(Final Answer)</em>

6 0
3 years ago
The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

Scanner input = new Scanner(System.in);

int row, col;  

System.out.print("Rows: ");    row = input.nextInt();

System.out.print("Cols: ");     col = input.nextInt();  

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){    

    for(int j =0;j<col;j++){

        Array2D[i][j] = input.nextInt();  

    }     }

 

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}  

public static int[] findmax(int[][] Array2D,int row, int col)   {  

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

        if(Array2D[i][j] > max){  

            maxitem[0] = i;

            maxitem[1] = j; } }    }

 

return maxitem;  

}  

}

Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

7 0
3 years ago
Complete the sentence.<br><br> A ___________search can be done on a list that is not ordered.
adelina 88 [10]

Answer:

Well, a binary search has to be ordered. So ima just say linear search..

Explanation:

I think its linear..

3 0
3 years ago
Read 2 more answers
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