All categories

3 years ago

In Microsoft Word you can access the _______ command from the "Mini toolbar

Computers and Technology

1 answer:

insens350 [35]3 years ago

4 0

The ''Save As'' command

You might be interested in

Which is a method used with arrays?<br><br> find<br><br> index<br><br> insert<br><br> sort

Furkat [3]

Answer:

Index

Explanation:

Got it right e2020

4 0

3 years ago

Please help me I am crying because I don't know

saw5 [17]

Answer:ubers texi’s

Explanation:

3 0

3 years ago

What is the indication when a student conducting an electronic search of the literature is simultaneously using two databases, p

aivan3 [116]

Generate more than 2000 citations is The keywords were not sufficiently narrowed.

<h3>Why utilize PubMed as a database?</h3>

PubMed is the standard database that is used in the healthcare profession. It has the ability to link to full-text articles, provides advance researching including filtering and superior queries and links to related articles.

<h3>What are the restrictions of PubMed?</h3>

The newest articles in PubMed may not yet be indexed for MEDLINE. There is a short lag time (a few days to many weeks) between when authorities enter the PubMed database and when they are described with MeSH terms. An article you require is not indexed for MEDLINE

To learn more about PubMed , refer

brainly.com/question/602370

#SPJ4

A. There has been a great deal of research in this area.

B. CINAHL and MEDLINE duplicate the literature.

C. The keywords were not sufficiently narrowed.

D. A third database is necessary to limit the search.

5 0

2 years ago

Need help fast this is do a 4

Stells [14]

Answer:

I believe the answer is B.

8 0

3 years ago

Note: You can use a word document to write your answers and copy-paste your answer to the area specified. a. (5 points) Convert

MrMuchimi

Answer:

$EA9_{16} = 3753$

$CB2_{16} = 3250$

$(1011 1110 1101 1011 1010)_2 = 781754$

$(1010 1000 1011 1000 1110 1101)_2 = 11057389$

$(1011 1110 1101 1011 1010)_2 = BEDBA$

$(1010 1000 1011 1000 1110 1101)_2 = A8B8ED$

$74510_8= 221416$

$67210_8 = 203212$

Explanation:

Solving (a): To base 10

$(i)\ EA9_{16$

We simply multiply each digit by a base of 16 to the power of their position.

i.e.

$EA9_{16} = E * 16^2 + A * 16^1 + 9 * 16^0$

$EA9_{16} = E * 256 + A * 16 + 9 * 1$

In hexadecimal

$A = 10; E = 14$

So:

$EA9_{16} = 14 * 256 + 10 * 16 + 9 * 1$

$EA9_{16} = 3753$

$(ii)\ CB2_{16}$

This gives:

$CB2_{16} = C * 16^2 + B * 16^1 + 2 * 16^0$

$CB2_{16} = C * 256 + B * 16 + 2 * 1$

In hexadecimal

$C = 12; B =11$

So:

$CB2_{16} = 12 * 256 + 11 * 16 + 2 * 1$

$CB2_{16} = 3250$

Solving (b): To base 10

$(i)\ (1011 1110 1101 1011 1010)_2$

We simply multiply each digit by a base of 2 to the power of their position.

i.e.

$(1011 1110 1101 1011 1010)_2 = 1 * 2^{19} + 0 * 2^{18} + 1 * 2^{17} + 1 * 2^{16} +1 * 2^{15} + 1 * 2^{14} + 1 * 2^{13} + 0 * 2^{12} + 1 * 2^{11} + 1 * 2^{10} + 0 * 2^9 + 1 * 2^8 +1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 1 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 0 * 2^0$

$(1011 1110 1101 1011 1010)_2 = 781754$

$(ii)\ (1010 1000 1011 1000 1110 1101)_2$

$(1010 1000 1011 1000 1110 1101)_2 = 1 * 2^{23} + 0 * 2^{22} + 1 * 2^{21} + 0 * 2^{20} +1 * 2^{19} + 0 * 2^{18} + 0 * 2^{17} + 0 * 2^{16} + 1 * 2^{15} + 0 * 2^{14} + 1 * 2^{13} + 1 * 2^{12} +1 * 2^{11} + 0 * 2^{10} + 0 * 2^9 + 0 * 2^8 + 1 * 2^7 + 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1*2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0$