What reason should kamal add to all of the question marks in order to completer the proof
1 answer:
Answer: The answers is alternate interior angles.
Step-by-step explanation: First of all, the questions marks given in the figure are renamed in the attached figure as (a), (b), (c) and (d).
For (a): Since AC is parallel to A'C' and A'D is a transversal for these two parallel lines, so, ∠CDB' = ∠B'A'C', because these are alternate interior angles.
For (b): Since BC is parallel to B'C' and A'B' is a transversal, so ∠BEB' = ∠A'B'C', because these are alternate interior angles.
For (c): Since AB is parallel to A'B' and AD is a transversal, so ∠BAC = ∠CDB', because these are alternate interior angles.
For (d): Since AB is parallel to A'B' and BE is a transversal, so ∠ABC = ∠BEB', because these are alternate interior angles.
Thus, all the questions marks are the reasons that the given angles are equal because they are alternate interior angles.
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Step-by-step explanation:
Here the total numbers are 1, 4, 3, 7, 6
Since the total number of possible arrangement =
The total number of the odd numbers in the given numbers = 3
Thus the possible arrangement that the first three digits will be odd numbers =
Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement =
=