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il63 [147K]
3 years ago
5

Find the selling price

Mathematics
1 answer:
tangare [24]3 years ago
6 0

the selling price would be 60.75

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What is the distance between (3, 7 and (15, 16)
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D = √( (x2 - x1)^2 + (y2 - y1)^2 )
D = √( (15-3)^2 + (16 - 7)^2 )
D = √ ( 12^2 + 9^2 )
D = √ (144 + 81)
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D = 15
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The thundering herd an amusement park ride is not open
ioda
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What is the slope of the line represented by the equation y = 4/5x-3?
dsp73

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C

Step-by-step explanation:

option C.

When in the form y= mx +q the slope of a line is given by the number multiplying x

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3 years ago
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Find the circumference of a circle that has a diameter of 4 m. Use 3.14 for pi. m
Arturiano [62]

Answer:

<h2>12.56 m</h2>

Step-by-step explanation:

The formula of a circumference of a circle:

C=d\pi

<em>d</em> - <em>diameter</em>

<em />

We have <em>d = 4m</em>.

Substitute:

C=4\pi\ m

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3 0
3 years ago
A. Complete the chart based on the initial conditions:
Nata [24]

Answer:

a.

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

b.

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form (a,ar,ar^2,ar^3...) where a-first \ term and r-common \ ratio

#Since the population is reducing, r can is obtained as r=1-r=0.94

#The n^t^h term is obtained using the formula x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

The ant's alive after 4 months is obtained as the value of x_5

x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: (a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

r=1.1 and a=80 and x_n=ar^(^n^-^1^)

The population after 4weeks will be:

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

8 0
4 years ago
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