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WITCHER [35]
1 year ago
6

There are 20 cartons that each contain a dozen eggs. Of allthe eggs. 60 are cracked. What percent of the eggs are cracked:Round

to the nearest percent, if necessary,
Mathematics
1 answer:
Helen [10]1 year ago
6 0

20 cartons

total of eggs = 20x12=240

240------ 100%

60------ x %

x is the percentage that represents 60 cracked eggs

x=\frac{60\cdot100}{240}=25

The percent of the eggs are cracked is 25%

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Answer:

  12x -y = -87

Step-by-step explanation:

You can start with the 2-point form of the equation of a line and manipulate it to give you the standard form.

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B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing
kenny6666 [7]

Answer:

\boxed{ \boxed{ \sf {Marked \: price \:  = Rs \: 1500}}}

\boxed{ \bold{ \boxed{ \sf{Selling \: price =  \: Rs \: 1230}}}}

Step-by-step explanation:

Let Cost price ( C.P ) be x

<u>Finding </u><u>the </u><u>Marked </u><u>price </u><u>and </u><u>selling </u><u>price </u>

Marked price = \sf{x + 20\% \: of \: x}

⇒\sf{x +  \frac{20}{100}  \times x}

⇒\sf{ \frac{x \times 100 + 20x}{100} }

⇒\sf{ \frac{120x}{100} } ⇒ ( i )

Selling price = \sf{marked \: price \:  - 18\% \: of \: marked \: price}

⇒\sf{ \frac{120x}{100} -  \frac{18}{100}  \times  \frac{120x}{100} }

⇒\sf{ \frac{120x}{100}  -  \frac{54x}{250} }

⇒\sf{ \frac{120x \times 5 - 54x \times 2}{500} }

⇒\sf{ \frac{600x - 108x}{500} }

⇒\sf{ \frac{492x}{500} } ⇒ ( ii )

<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x </u><u>(</u><u> </u><u>Cost </u><u>price </u><u>)</u>

\sf{loss = cost \: price - selling \: price}

⇒\sf{20 = x -  \frac{492x}{500} }

⇒\sf{20  =  \frac{x \times 500 - 492x}{500} }

⇒\sf{20 =  \frac{8x}{500} }

⇒\sf{8x = 10000}

⇒\sf{x =  \frac{10000}{8} }

⇒\sf{x = \: Rs \:  1250}

Value of x ( cost price ) = Rs 1250

<u>Now</u><u>,</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>i </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>marked </u><u>price</u>

\sf{marked \: price =  \frac{120x}{100} }

⇒\sf{ \frac{120 \times 1250}{100} }

⇒\sf{   \: Rs \: 1500}

<u>Replacing </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>ii </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>selling </u><u>price</u>

\sf{selling \: price =  \frac{492 \: x}{500} }

⇒\sf{ \frac{615000}{500} }

⇒\sf{ \: Rs \: 1230}

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0
4 years ago
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