X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer:
870 as it is the only number in the list which closest and lesser then 956.
(if you divide, then you get 10 as quotient and 86 as remainder)
we can also take 87 but the question mentions with multiples of 10.
Step-by-step explanation:
Answer = 8y
Step-by-step explanation:
if an octagon has 8 sides and each side is = to y then the total side length in the primiter is = to 8sides times y or 8y
So, put your "x's" together first and then your intercepts. That should answer your question :)
Answer:
d
Step-by-step explanation:
