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sukhopar [10]
2 years ago
6

In Spring, Jack trimmed his tree 3 in. Shorter. In the summer he trimmed it 5 more inches. The tree is now 45 in. Tall. How tall

was the tree before Jack trimmed it?
Mathematics
2 answers:
sergejj [24]2 years ago
7 0

Answer: 53 inches

Step-by-step explanation:3+5=8

45+8= 53

iren2701 [21]2 years ago
4 0
It was 53 inches because 45+3+5=53 inches total
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Answer:

They are all positive because you must go right.

They are all negative because you must go down.

Step-by-step explanation:

Example. (1,-4)

You go over one.

Down 4

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3 years ago
Henry drives at a speed of 80 miles per hour. <br> How long will it take to drive 400 miles?
mart [117]

Answer:

5hrs

Step-by-step explanation:

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4 0
2 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Write two subtraction equations to show how to find 15 - 7
pantera1 [17]
15-7=8         
i hope it helps
5 0
3 years ago
Read 2 more answers
H + 1/3 when h= 1 2/3
Bess [88]
2. Because if 1/3 + 2/3 is 1 then 1+1=2
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3 years ago
Read 2 more answers
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