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Flauer [41]
3 years ago
8

Evaluate the expression when x = 6.

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0
3x + 7

where x =6


3*6 + 7
18 + 7 = 25
ANEK [815]3 years ago
6 0
Evaluate for x=6

(3)(6)+7

18 + 7

=25

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What is the correct letter? (Giving brainliest)
vampirchik [111]

Answer:

d is the answer

Step-by-step explanation:

perimeter of rect = 2(7+3) = 20

perimeter of square = 4 a =20

a = 5

3 0
3 years ago
3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

a_n=a_1+(n-1)\,d

That in our case would give:

a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11

b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

5 0
3 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0
3 years ago
Multiply or divide. Show your work.<br><br> 5x+10/x+2*2x/4x-10
jolli1 [7]
\frac{5x + 10}{x + 2} * \frac{2x}{4x - 10} = \frac{5(x) + 5(2)}{x + 2} * \frac{2x}{2(x) - 2(5)} = \frac{5(x + 2)}{x + 2} * \frac{2x}{2(x - 5)} = \frac{5}{1} * \frac{x}{x - 5} = \frac{5x}{x - 5}
5 0
4 years ago
DASAROLLA:<br><br>a) (x+3) (x+5)=<br><br>b) (x+4) (x-5)=​
Nat2105 [25]

Answer:

a)x^{2}+8x+15

b)x^{2}-x-20

Step-by-step explanation:

a) (x+3)(x+5)

a)x^{2}+5x+3x+15

a)x^{2}+8x+15

b) (x+4)(x-5)

b) x^{2}-5x+4x-20

b)x^{2}-x-20

8 0
3 years ago
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