the sum of supplementary angles is 180 degree
therefore
x +2x = 180°
3x = 180
X = 180/3 = 60°
the value of X is 60°
Answer:
Canadian railcars show weight figures in both imperial and metric. Canadian railways also maintain exclusive use of imperial measurements to describe train length and height in feet and train masses in short tons. Canadians typically use a mix of metric and imperial measurements in their daily lives.
The ratio of the sides of the given similar triangles is: C. 4/12 = 5/15 = 1/3.
<h3>How do the Sides of Similar Triangles Relate?</h3>
The corresponding sides of similar triangles have ratios that are equal to each other.
The corresponding sides and their ratios are:
4/12 = 1/3
5/15 = 1/3
Therefore, the ratio of their sides in its lowest term is:
C. 4/12 = 5/15 = 1/3
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First, when multiplying percents, you need to convert them to decimals. You convert percents to decimals by multiplying by 100 or moving the decimal two places to the left. Once you convert them to full decimals, you multiply the decimal by the number that you are getting the percentage from
61% of 180⇒.61×180=<u>109.8 </u>
5.1% of 81?⇒.051×81=<u>4.131
</u>
of 36?⇒16.5×36⇒.165×36=<u>5.94
</u>81% of 241⇒.81×241=<u>195.21</u>
76% of 600⇒.76×600=<u>456</u>
88% of 680⇒.88×680=<u>598.4</u>
37% of 481⇒.37×481=<u>177.97</u>
19.1% of 380⇒.191×380=<u>72.58</u>
41% of 321⇒.41×321=<u>131.61</u>
33% of 331⇒.33×331=<u>109.23</u>
The cost of small box of oranges is $7.
The cost of large box of oranges is $13.
<u>Step-by-step explanation:</u>
It is given that,
3 small boxes of oranges and 14 large boxes of oranges for a total of $203.
11 small boxes of oranges and 11 large boxes of oranges for a total of $220.
Let us take,
- The cost of small box of oranges = x
- The cost of large box of oranges = y
<u>The system of equations are framed as :</u>
3x + 14y = 203 ---------(1)
11x + 11y = 220 ---------(2)
<u>To solve these equations for x and y values :</u>
Multiply equation (1) by 11 and equation (2) by 3
Subtract eq(2) from eq(1),
33x + 154y = 2233
- <u>(33x + 33y = 660) </u>
<u> 121 y = 1573 </u>
⇒ y = 1573 / 121
⇒ y = 13
∴ The cost of large box of oranges is $13.
Substitute y=13 in the eq(1),
⇒ 3x + 14(13) = 203
⇒ 3x + 182 = 203
⇒ 3x = 203 - 182
⇒ 3x = 21
⇒ x = 21 / 3
⇒ x = 7
∴ The cost of small box of oranges is $7.
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