Answer: 1
Step-by-step explanation:
From the given picture, it can be seen that there is a plane H on which two pints J and K are located.
One of the Axiom in Euclid's geometry says that <em>"Through any given two points X and Y, only one and only one line can be drawn "</em>
Therefore by Axiom in Euclid's geometry , for the given points J and K in plane H , only one line can be drawn through points J and K.
<u>Given</u>:
The given expression is ![(\sqrt{5})( \sqrt[3]{5})](https://tex.z-dn.net/?f=%28%5Csqrt%7B5%7D%29%28%20%5Csqrt%5B3%5D%7B5%7D%29)
We need to simplify the given expression.
<u>Simplification</u>:
Let us simplify the given expression.
Rewriting the given expression, we have;

Let us apply the exponent rule
, we get;

Taking LCM, we have;

Simplifying, we get;

Thus, the simplified value of the given expression is 
Hence, Option a is the correct answer.
Answer:
y=(1/5)x-5
Step-by-step explanation:
The given equation is
y=(1/5)x+4
This is of the form
y=mx+b
which is called the slope-intercept form because
m is the slope
b is the y intercept.
In this case,
m=1/5
b=4
you can see from the chart that this matches the red line.
If two lines are parallel, they must have the same slope. So we know that the slope of the desired line is 1/5. So, now we know that
y=(1/5)x+b
Since the line must go through the point (5,-4), we have
-4=(1/5)(5)+b
-4=1+b
b=-5
So, the desired line is
y=(1/5)x-5
9514 1404 393
Answer:
250
Step-by-step explanation:
Let 'a' represent the number of adult tickets.
a +(a -73) = 427
2a = 500 . . . . . add 73
a = 250 . . . . . . divide by 2
250 adult tickets were sold.
_____
<em>Additional comment</em>
I call this a "sum and difference problem" because we are given the total of two values and the difference between them. As you can see here, the larger of the two values is the average of the given numbers, their sum divided by 2. This is the generic solution to such a problem: the larger number is the average of the given sum and difference.
Answer:
7
Step-by-step explanation:
-3 + 3 = 0
0 + 4 = 4
4 + 3 = 7