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Paraphin [41]
3 years ago
7

Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:

Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Svetlanka [38]3 years ago
4 0

Answer:

1. B, E

2. B, E

3. B

4. B

5. D

6. A

7. D

8. A

9. B

10. B

11. A

Step-by-step explanation:

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<h3>What is the perpendicular bisector theorem?</h3>

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