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Paraphin [41]
3 years ago
7

Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:

Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)

</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so

</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>

</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>

remember that 
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and 
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Svetlanka [38]3 years ago
4 0

Answer:

1. B, E

2. B, E

3. B

4. B

5. D

6. A

7. D

8. A

9. B

10. B

11. A

Step-by-step explanation:

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Use proper probability notation. Identify function and label inputs when using technology.
zhannawk [14.2K]

Answer:

0.1349

Step-by-step explanation:

Given that:

Sample size, n = 500

20% of 500 ; 0.2 * 500 = 100

p = 0.18 ; n = 500 ; 1 - p = 0.82

P(x ≥ 100) ;

Using the binomial probability relation :

P(x =x) = nCx * p(x)^x * (1 - p)^(n - x

P(x ≥ 100) = 500C100 * 0.18^100 * 0.82^400

P(x ≥ 100) = 0.1349

5 0
3 years ago
Expon
Tema [17]

A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms. This can be obtained by understanding what like radicals are.

<h3>Which sets of the radical expressions listed could be considered like terms as written?</h3>
  • Radical expression: Radical expression is an equation that has a variable in a radicand (expression under the root) or has a variable with a rational exponent.

For example, √128, √16

  • Like radicals: Radicals that have the same root number and radicand (expression under the root)

For example, 2√x and 5√x are like terms.

Here in the question radical expressions are given,

  • 5∛2x
  • -4x∛2
  • 5√2x
  • -3∛2x
  • 5x√2x

By definition of like radicals we get that 5∛2x and -3∛2x are like terms since root number and radicand are same, that is, root number is 3 and radicand is 2x.

Hence A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms.

Learn more about radicals here:

brainly.com/question/16181471  

#SPJ9

3 0
2 years ago
Find the missing coefficient (4d—4)(3d—2)=12d^2+ []d+8
sergij07 [2.7K]
<span>(4d-4)(3d-2)=12d^2 + []d + 8

Using FOIL method:
4d x 3d = 12d^2
4d x  -2 = -8d
-4 x 3d = -12d
-4 x -2 = 8

Adding common terms, we have:
-8d + -12d = -20 d

The missing coefficient is -20.</span>
8 0
3 years ago
Please help me solve these.
ale4655 [162]
Oh gosh i wish i knew how to do that what grade are u in cause i remember having that last year but dont remember.
5 0
3 years ago
NEED HELP ASAP
stellarik [79]

C

because you just eliminate it

3 0
3 years ago
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