We have that <span>tan(theta)sin(theta)+cos(theta)=sec(theta) </span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta) </span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator so
remember that </span>sin²(theta)+cos²(theta)=1 {[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta) and 1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.) He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
