Hi! In geometry, two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.<span>
Hope this helps!
Love, grace-
</span>
Answer:
or ![(-\infty, 47/6]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%2047%2F6%5D)
Step-by-step explanation:
Note that 
.
Also, note that 
.
So, the inequality is really equal to 
.
We can then add 
to both sides to get .
So, the solution is , or in interval notation,
I don't know the area of a parallelogram off the top of my head but you can use the area of the rectangle and the area of the triangle and add those. The area of the triangle is 1/2*base*height and use the pythagorean theorem to find the base. 3² + b² = 5²; 9 + b² = 25; b² = 16; b = 4. The area of the triangle is 1/2*4*3 or 6 in. Since there are two of them, the total area of the triangles are 12 in. The area of the rectangle is length*width or (12 - 4) * 3 which is 8 * 3 or 24in. Add these areas together to get 36in total
F(x) = (x - 4) (x^2 + 4) would be your answer.
Answer:
C.
x + 0.05x = 3.15, which has one solution
Step-by-step explanation:
Let x = the price Joshua pays for the pack of pens
He add 5% (=.05 in decimal form)
That is x* .05
The new cost is 3.15
x+.05x = 3.15
This will have one solution
