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Pepsi [2]
3 years ago
5

The Internet has made it possible for most people to order all of their clothing online. While this may be a preference for some

people, most people still go to shopping malls and stores to purchase their clothing. People might give a variety of reasons for not wanting to use the Internet exclusively. What likely accounts for the difference in preference
Computers and Technology
1 answer:
suter [353]3 years ago
3 0

Answer:

Explanation:

Based on the information provided in this scenario it can be said that this is likely due to there being a cultural lag between having the Internet and using the technology to its full capacity. Cultural lag refers to the notion that culture takes time to catch up with technological innovations, mainly due to not everyone has access to the new technology. As years pass a specific technological advancement becomes more readily accessible to the wider public as is thus more widely adopted.

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This is for C++: Using a nested for loop output the following pattern to the screen:
olga55 [171]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int r=26,x,y;//defining integer variable  

char c;//defining a character variable

for(x= 1; y<= r; x++)//using for loop for count value

{

for(y= 1; y<= x; y++)//using for loop to convert value in triangle  

{

c=(char)(y+64);//convert value into character  

cout << c;//print character value

}

cout << "\n";//use print method for line break

}

return 0;

}

Output:

Please find the attachment file.

Explanation:

In this code, three integer variable "x,y, and r", and one character variable "c" is declared, that is used in the nested for loop,  in the first for loop it counts the character value and in the next for loop, it converts the value into a triangle and uses the char variable to print its character value.

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3 years ago
Which of the following are characteristics of conditional formatting? Choose all that apply.
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Read 2 more answers
JAVA
avanturin [10]

Answer:

   public ArrayList onlyBlue(String[] clothes){

       ArrayList<String> blueCloths = new ArrayList<>();

       for(int i =0; i<clothes.length; i++){

           if(clothes[i].equalsIgnoreCase("blue")){

               blueCloths.add(clothes[i]);

           }

       }

       return blueCloths;

   }

Explanation:

  • Create the method to accept an Array object of type String representing colors with a return type of an ArrayList
  • Within the method body, create and initialize an Arraylist
  • Use a for loop to iterate the Array of cloths.
  • Use an if statement within the for loop to check if item equals blue and add to the Arraylist.
  • Finally return the arrayList to the caller
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Answer:

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