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Lapatulllka [165]
3 years ago
6

Brenda wants to finish her presentation with a summary slide . She wants three key messages to appear on each of the photo clips

. how can she provide this effect ?
Brenda can first include an ________ and then include______ . Lastly she can just provide an _____ effect to the text to appear one by one each photo clip .

for question 1 : image , object , or animation
for question 2 : video , text , or shapes
for question 3: audio , enhanced , animation
Computers and Technology
2 answers:
igomit [66]3 years ago
5 0

Answer:

Brenda can first include an (1) image and then include (2) text. Lastly she can just provide an (3) animation effect to the text to appear one by one each photoclip.

Explanation:

To create the image Brenda wants, she would have to include three images with text on them and to make them appear one by one on each photoclip, she would use an animation clip to do so.

Sav [38]3 years ago
4 0

Brenda can first include an image and then include text. Lastly she can just provide an enhanced effect to the text to appear one by one each photo clip.

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Write a program to implement problem statement below; provide the menu for input N and number of experiment M to calculate avera
zalisa [80]

Answer:

Explanation:

#include<iostream>

#include<ctime>

#include<bits/stdc++.h>

using namespace std;

double calculate(double arr[], int l)

{

double avg=0.0;

int x;

for(x=0;x<l;x++)

{

avg+=arr[x];

}

avg/=l;

return avg;

}

int biggest(int arr[], int n)

{

int x,idx,big=-1;

for(x=0;x<n;x++)

{

if(arr[x]>big)

{

big=arr[x];

idx=x;

}

}

return idx;

}

int main()

{

vector<pair<int,double> >result;

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

int choice;

cin>>choice;

while(choice!=2)

{

int n,m;

cout<<"Enter N"<<endl;

cin>>n;

cout<<"Enter M"<<endl;

cin>>m;

int c=m;

double running_time[c];

while(c>0)

{

int arr[n];

int x;

for(x=0;x<n;x++)

{

arr[x] = rand();

}

clock_t start = clock();

int pos = biggest(arr,n);

clock_t t_end = clock();

c--;

running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;

}

double avg_running_time = calculate(running_time,m);

result.push_back(make_pair(n,avg_running_time));

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

cin>>choice;

}

for(int x=0;x<result.size();x++)

{

cout<<result[x].first<<" "<<result[x].second<<endl;

}

}

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3 years ago
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