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mezya [45]
3 years ago
15

Why do the symbols at right not constitute an equation

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
5 0

symbols at th rihht?

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Please help!<br><br> Simplify (2x-3y)^10
pantera1 [17]

Answer:

hope this helps! (O>O)

Step-by-step explanation:

4 0
4 years ago
If f(x)=3x+2/5x-3; then f-1(x) is <br>a.5x-3/3x+2<br>b3x-2/5x+3<br>c.3x+2/5x-3<br>d.2-3x/3-5x<br>​
valentinak56 [21]
Answer is a because -1 just means the opposite
5 0
3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 6x3 ? 9x2 ? 108x + 2, [?3, 4]
SVEN [57.7K]
Assuming the question marks are minus signs
to find max, take derivitive and test 0's and endpoints

take derivitive
f'(x)=18x²-18x-108
it equal 0 at x=-2 and 3
if we make a sign chart to find the change of signs
the sign changes from (+) to (-) at x=-2 and from (-) to (+) at x=3
so a reletive max at x=-2 and a reletive min at x=3

test entpoints

f(-3)=83
f(-2)=134
f(3)=-241
f(4)=-190

the min is at x=3 and max is at x=-2
4 0
4 years ago
Can someone help with this.
olya-2409 [2.1K]

Answer:

A. S+A

B. (4×3)+(6×2)=$24

8 0
3 years ago
I DONT UNDERSTAND HELP
Taya2010 [7]

Step-by-step explanation:

By Geometric mean property:

{16}^{2}  = x \times 3x \\  \\  \therefore \: 3 {x}^{2}  =  {16}^{2}  \\  \\ \therefore \:  {x}^{2}  =   \frac{{16}^{2} }{3} \\  \\ \therefore \:  {x}  =   \sqrt{ \frac{{16}^{2} }{3} }  \\  \\ \therefore \:  {x}  =   {  \frac{16}{ \sqrt{3} } } \\  \\ \therefore \:  {x}  =   {  \frac{16 \sqrt{3} }{ 3} } \\  \\ \therefore \:  {x}  =   {  \frac{16  \times 1.732}{ 3} } \\  \\ \therefore \:  {x}  =   {  \frac{27.712}{ 3} }\\  \\ \therefore \:  {x}  =   9.23733333 \\  \\  \huge \red{ \boxed{ \bold{\therefore \:  {x}  =   9.24}}}

8 0
4 years ago
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