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Papessa [141]
4 years ago
5

Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 6x3 ? 9x2 ? 108x + 2, [?3, 4]

Mathematics
1 answer:
SVEN [57.7K]4 years ago
4 0
Assuming the question marks are minus signs
to find max, take derivitive and test 0's and endpoints

take derivitive
f'(x)=18x²-18x-108
it equal 0 at x=-2 and 3
if we make a sign chart to find the change of signs
the sign changes from (+) to (-) at x=-2 and from (-) to (+) at x=3
so a reletive max at x=-2 and a reletive min at x=3

test entpoints

f(-3)=83
f(-2)=134
f(3)=-241
f(4)=-190

the min is at x=3 and max is at x=-2
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we have that

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For a club gathering you were having, you bought a total of 50 burgers, and spent $90. You paid $2 per turkey burger, and $1.50
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Answer:

<u></u>

  • <u>No. You would have to cut the number of veggie burgers in more than half.</u>

Explanation:

<u>1. Model the situation with a system of equations</u>

<u />

<u>a) Name the variables:</u>

  • number of turkey burgers: t
  • number of veggie burgers: v

<u />

<u>b) Number of burgers:</u>

  • 50 = t + v

<u />

<u>c) Cost of the 50 burgers:</u>

  • $90 = 2t + 1.50v

<u>2. Solve that system of equations:</u>

<u />

<u>a) System</u>

  • 50 = t + v
  • 90 = 2t + 1.50v

<u>b) Mutliply the first equation by 2 and subtract the second equation</u>

  • 100 = 2t + 2v
  •  90 = 2t + 1.50v

  • 10 = 0.5v
  • v = 20 ⇒ t = 50 - 20 = 30

<u />

<u>c) How much would you spend if the next year you buy the double of 20 turkey burgers (40) and the half of 30 veggie burgers (15)</u>

  • $2(40) + $1.50(15) = $80 + $22.50 = $102.50

Then, you if you double the number of turkey burgers, and cut the number burgers in half, you would spend more than $90 ($102.50).

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