Answer:
645 ÷ 50 = 12.9
I hope this helps and that you have a wonderful day ^‿^
The equation of the tangent line will be y = -3x + 8.
<h3>What is a linear equation?</h3>
A straight line on the coordinate plane is represented by a linear equation.
A linear equation always has the same and constant slope.
The formula for a linear function is f(x) = ax + b, where a and b are real values.
Given curve
f(x) = x² - 7x + 12
The slope of the tangent equation = the first derivative of a function at that point (2,2).
So,
f'(x) = m = 2x - 7
At (2,2) ⇒ m = -3
Now let's say the equation of tangent
y = mx + c
2 = (-3)2 + c
c = 8
So,
Equation of tangent line on the curve f(x) = x² - 7x + 12 will be y = -3x + 8.
For more about the linear equation,
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ONO THAT NOT THE ANSWER THIS IS [3,628,800] 10P10=10, AND 0!= 10 TIMES 9 TIMES 8 TIMES 7 TIMES 6 TIMES 5 TIMES 4 TIMES 3 TIMES 2 TIMES 1= 3,628,800.
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2