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AysviL [449]
3 years ago
13

There are 9 yellow and 4 purple balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probab

ility of choosing 1 yellow ball and then 2 purple balls?
Question 5 options:

165/5210


24/1329


144/2197


28/1335
Mathematics
2 answers:
ahrayia [7]3 years ago
7 0
Did you get a answer?
amid [387]3 years ago
5 0

The <em>correct answer</em> is:


144/2197


Explanation:


Drawing the balls with replacement means that the events are independent. This means to find the probability of all 3 balls being drawn, we multiply.


The probability of drawing a yellow ball is 9/13, since there are 9 yellow balls out of 13 total.

The probability of drawing the first purple ball is 4/13, since there are 4 purple balls out of 13 total.

The probability of drawing the second purple ball is 4/13, since there are still 4 purple balls out of 13 total.


This gives us:

(9/13)(4/13)(4/13) = (9*4*4)/(13*13*13) = 144/2197.

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6 0
3 years ago
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dlinn [17]
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8 0
3 years ago
Can someone explain this step by step please
kobusy [5.1K]

Answer:

x = - 2

y = 6

Step-by-step explanation:

The best way to do this is to put - 3x in for y in the second equation.

4x - 2(-3x) = - 20        Watch the signs. You have 2 minus signs.

4x - - 6x = -20            Change - - 6x to 6x

4x + 6x = - 20              Add

10x = - 20                   Divide by 10

x = -20/10

x = - 2

============================

Find y

y = - 3x

y = -3 * -2

y = 6

3 0
2 years ago
Can u help with this plzz
Rama09 [41]

Answer:

Umm, it's just a black screen

Step-by-step explanation:

My only answer is that you turn a light on or something.Where's the question?

8 0
3 years ago
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Ymorist [56]
The answer to your question is y=-5
6 0
3 years ago
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