All categories

3 years ago

How do I solve 8760-1353?

Mathematics

1 answer:

posledela3 years ago

3 0

Answer:

7507

Step-by-step explanation:

8760-1253=7507

You might be interested in

Solve the system by using matrices.<br> X = 4<br> X + y = -6<br> 4x - 3y + 2z = 26

Viktor [21]

Answer:

x=4, y=-10, z=-10

Step-by-step explanation:

7 0

3 years ago

Forgot to add pictures but are these answers correct? Brainliest

nignag [31]

Answer:

i think so!

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Transitive property: if 3x plus y equals 7 and 7 equals 5x minus 2y then

kap26 [50]

3x + y = 7
7 = 5x - 2y

THEN 3x + y = 5x - 2y ... it's like you're taking out the middle man "7"

7 0

4 years ago

From Euler’s relation eiθ = cosθ + isinθ,

adelina 88 [10]

Answer:

(a) The graphic representation is in the attached figure.

(b) $\cos(\theta) = \frac{e^{i\theta} + e^{-i\theta}}{2}$ .

(c) $\sin(\theta) = \frac{e^{i\theta} - e^{-i\theta}}{2i}$ .

Step-by-step explanation:

(a) Given a complex number $e^{i\theta}$ we know, from Euler's formula that $e^{i\theta} = \cos(\theta)+i\sin(\theta)$ . So, it is not difficult to notice that

$|e^{i\theta}|^2 = \cos^2(\theta)+\sin^2(\theta) =1$

so it is on the unit circumference. Also, notice that the Cartesian representation of the complex number is $(\cos(\theta), \sin(\theta))$ .

Now,

$e^{-i\theta} = \cos(\theta)+i\sin(-\theta) = \cos(\theta)-i\sin(\theta)$ .

Notice that $e^{-i\theta}$ has the same modulus that $e^{i\theta}$ , so it is on the unit circumference. Beside, its Cartesian representation is $(\cos(\theta), -\sin(\theta))$ .

So, the points $(\cos(\theta), \sin(\theta))$ and $(\cos(\theta), -\sin(\theta))$ are symmetric with respect to the X-axis. All this can be checked in the attached figure.