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3 years ago

Evaluate the square root of x^2 - 5x when x = 7. Round your answer to the nearest hundredth

Mathematics

2 answers:

Troyanec [42]3 years ago

5 0

X^2-5x, given x=7,

(7)^2-5(7)=14

sqrt(14)=3.74

sesenic [268]3 years ago

3 0

OK, 72−(5)(7)=14
Its 14 because you plug in the sevens then you get 49-35 which is 14. Hope this answer helps you and mark as brainliest! :)

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Solving and graphing absolute value equations

Monica [59]

$\begin{gathered} -4\text{ + 7}x\text{ }\leq6x\text{ + 2} \\ 7x-6x\leq2+4 \\ x\text{ }\leq6 \end{gathered}$

6 0

1 year ago

Caiden and Josh are practicing at a batting cage. Josh has hit nine more than one-half the number of balls that Caiden has. If t

OverLord2011 [107]

Answer:

The Answer is: Josh hit 47 balls.

Step-by-step explanation:

Let j = Josh number of hits and c = Caiden number of hits:

j = c/2 + 9

Total:

j + c = 123.

Substitute:

(c/2 + 9) + c = 123

c/2 + c = 123 - 9

c/2 + c = 114

1/2c + 2/2c = 114

3/2c = 144

c = 144 (2/3) = 76, Number of hits for Caiden

Solve for j:

j = 76/2 + 9

j = 38 + 9 = 47, number of hits for Josh

Proof:

j + c = 123

47 + 76 = 123

123 = 123

Hope this helps! Have an Awesome Day!! :-)

6 0

4 years ago

A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime

MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let $\mu$ = true average percentage of organic matter

So, Null Hypothesis, $H_0$ : $\mu$ = 3% {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, $H_A$ : $\mu \neq$ 3% {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean percentage of organic matter = 2.481%

s = sample standard deviation = 1.616%

n = sample of soil specimens = 30

So, the test statistics = $\frac{2.481-3}{\frac{1.616}{\sqrt{30} } }$ ~ $t_2_9$

= -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0

3 years ago

What is the measure of the radius of the cone in the diagram below?

Anastasy [175]

Answer:

4cm

Step-by-step explanation:

the diameter is labelled as 8cm

radius is half of the diameter

3 0

3 years ago

(20 points)

vladimir1956 [14]

Answer:

Step-by-step explanation:

Slope is the same(x) therefore they are parallel

3 0

4 years ago