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lina2011 [118]
3 years ago
11

Need help with 18 and 20 would be appreciated you need to find the variable

Mathematics
1 answer:
torisob [31]3 years ago
7 0

18: X. is 30 as well. Y. is 15 dont have the answer for z.

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Options... <br>1.&lt;F<br>2.&lt;MFE<br>3.EFD<br><br>Plz answer <br>​
hoa [83]

Answer:

Angle F, or 1; see below

Step-by-step explanation:

When two triangles are congruent, everything about them is equal. Angle C is congruent F because they are in the same position on the triangle.

3 0
3 years ago
Whats the area help me youll get brainliest answer
victus00 [196]

Answer:

<h2>Area = 14m²</h2>

<u>Step-by-step explanation:</u>

area of rectangle = length × breadth

area of rectangle = 4 × 2

area of rectangle = 8m²

area of Triangle = 1/2 × base × height

area of Triangle = 1/2 × 4 × 3

area of Triangle = 6m²

Total area = 8 + 6

Total area = 14m²

3 0
3 years ago
5x-3x(26x-7x-28x) systems of equation
labwork [276]

Simplifying
5x + 2(8x + -9) = 3(x + 4) + -5(2x + 7)

Reorder the terms:
5x + 2(-9 + 8x) = 3(x + 4) + -5(2x + 7)
5x + (-9 * 2 + 8x * 2) = 3(x + 4) + -5(2x + 7)
5x + (-18 + 16x) = 3(x + 4) + -5(2x + 7)

Reorder the terms:
-18 + 5x + 16x = 3(x + 4) + -5(2x + 7)

Combine like terms: 5x + 16x = 21x
-18 + 21x = 3(x + 4) + -5(2x + 7)

Reorder the terms:
-18 + 21x = 3(4 + x) + -5(2x + 7)
-18 + 21x = (4 * 3 + x * 3) + -5(2x + 7)
-18 + 21x = (12 + 3x) + -5(2x + 7)

Reorder the terms:
-18 + 21x = 12 + 3x + -5(7 + 2x)
-18 + 21x = 12 + 3x + (7 * -5 + 2x * -5)
-18 + 21x = 12 + 3x + (-35 + -10x)

Reorder the terms:
-18 + 21x = 12 + -35 + 3x + -10x

Combine like terms: 12 + -35 = -23
-18 + 21x = -23 + 3x + -10x

Combine like terms: 3x + -10x = -7x
-18 + 21x = -23 + -7x

Solving
-18 + 21x = -23 + -7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7x' to each side of the equation.
-18 + 21x + 7x = -23 + -7x + 7x

Combine like terms: 21x + 7x = 28x
-18 + 28x = -23 + -7x + 7x

Combine like terms: -7x + 7x = 0
-18 + 28x = -23 + 0
-18 + 28x = -23

Add '18' to each side of the equation.
-18 + 18 + 28x = -23 + 18

Combine like terms: -18 + 18 = 0
0 + 28x = -23 + 18
28x = -23 + 18

Combine like terms: -23 + 18 = -5
28x = -5

Divide each side by '28'.
x = -0.1785714286

Simplifying
x = -0.1785714286
3 0
3 years ago
Express the following the ratio in the simplest term<br> A 45;6 B 54;36 C 12;8;16
spayn [35]
<span>A. 45:6 = 15:2
   
B. 54:36 = 3:2
   
C. 12:8:16 = 3:2:4</span>
8 0
3 years ago
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
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