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2 years ago

Need help with 18 and 20 would be appreciated you need to find the variable

Mathematics

1 answer:

torisob [31]2 years ago

7 0

18: X. is 30 as well. Y. is 15 dont have the answer for z.

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Sam ran 3 1/4 miles on Tuesday and then ran 2 5/6 miles on Wednesday. How many total miles did Sam run ?

julsineya [31]

Answer:

6 1/12 miles total

Step-by-step explanation:

3 1/4 = 13/4

2 5/6 = 17/6 to ADD fractions, you must have a common denominator

I will use 12 for these

13/4 = 39/12

17/6 = 34 /12

now you can add and simplify 39/12 + 34/12 = 73/12 = 6 1/12 miles

4 0

1 year ago

What is the solution of the equation 3x=12 round your answer to the nearest ten thousandth

Radda [10]

Answer:

2.2916

Step-by-step explanation:

Imagine bannanas flying into your room? I mean I couldn't imagine that either but im just saying

7 0

3 years ago

SAT scores are normally distributed with a mean of 1,500 and a standard deviation of 300. An administrator at a college is inter

Rama09 [41]

Answer:

The administrator should sample 968 students.

Step-by-step explanation:

We have to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.88}{2} = 0.06$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a p-value of $1 - 0.06 = 0.94$ , so Z = 1.555.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation of 300.

This means that $n = 300$

If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?

This is n for which M = 15. So

$M = z\frac{\sigma}{\sqrt{n}}$

$15 = 1.555\frac{300}{\sqrt{n}}$

$15\sqrt{n} = 300*1.555$

Dividing both sides by 15

$\sqrt{n} = 20*1.555$

$(\sqrt{n})^2 = (20*1.555)^2$

$n = 967.2$

Rounding up:

The administrator should sample 968 students.

5 0

2 years ago

The growth rate of nominal gdp between 1998 9063 <br> and 2018 20501 was

Alex73 [517]

Answer:

The nominal GDP growth rate between 1998 and 2018 was 126.20 percent.

Step-by-step explanation:

Given that in 1998 the country's GDP was $ 9,063 and in 2018 it was $ 20,501, to determine the nominal growth rate of the nation's GDP, the following calculation must be made:

9,063 = 100

20,501 = X

((20,501 x 100) / 9,063) = X

2,050,100 / 9,063 = X

226.20 = X

226.20 - 100 = 126.20

Therefore, the nominal GDP growth rate between 1998 and 2018 was 126.20 percent.

8 0

3 years ago

I don’t know how to do this I thought it was no slope but it’s wrong

tino4ka555 [31]

Answer:

Step-by-step explanation: Since there is a straight line not going up or down it is 0

7 0

3 years ago

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