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vladimir1956 [14]
3 years ago
14

there are 8 students who have 3/4 of a cake they want to share how much of the cake will each person gets if they split it evenl

y
Mathematics
1 answer:
Nostrana [21]3 years ago
7 0
You have 3/4 divided by 8 or 8/1

3/4 ÷ 8/1
3/4 x 1/8 = 3/32

Each person gets 3/32 of the original cake.

Here's another way to think of it:
Each person gets 1/8 of 3/4, so you multiply 1/8 times 3/4
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What is the solution to the equation below? Round to two decimal places. 2*in x=6.8
jek_recluse [69]

2\ln x=6.8\\ \ln x=3.4\\ x=e^{3.4}\approx29.96

7 0
3 years ago
I am lost can anyone help
Rina8888 [55]

I would recommend taking a picture of the instructions because I am not sure if you need to find the equation of the line that is parallel or perpendicular, so I will do both.

1. (3 , 2); y = 3x - 2

If the line is parallel to the given equation, the slopes have to be the SAME, so the slope(m) is 3

y = mx + b

y = 3x + b

To find b you plug in the point (3, 2) into the equation

2 = 3(3) + b

2 = 9 + b

-7 = b

The equation of the line that is parallel to the given equation is:

y = 3x - 7


To find the equation of the line that is perpendicular to the given equation, the slope has to be the exact opposite of the given slope. (you flip the sign and the number of the given slope to get the perpendicular line's slope)

The given slope is 3, the perpendicular slope is -\frac{1}{3}

y = mx + b

y = -\frac{1}{3} x + b

To find b, you plug in the point (3 , 2) into the equation

2 = -\frac{1}{3} (3) + b

2 = -1 + b

3 = b

The equation of the line perpendicular to the given equation is:

y = -\frac{1}{3} x +3

8 0
3 years ago
25a^2-30a+9 factor ?
CaHeK987 [17]

Factor 25a2−30a+9

25a2−30a+9

=(5a−3)(5a−3)

Answer:

(5a−3)(5a−3)


4 0
3 years ago
Y = log2 (x – 4)<br><br> How do I solve this
Dominik [7]
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7 0
2 years ago
The equation V = 16300 (0.94)^t represents the value (in dollars) of a car t years after its purchase. Use this equation to comp
Dafna1 [17]

Solution:

Given:

V=16300(0.94)^t

The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}

Hence,

\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\  \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\  \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

5 0
9 months ago
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