**Answer:**

not simaller i hope this helped

I think it’s circle :) hope it helped

**<u>Given</u>****<u> </u>****<u>info:</u>****<u>-</u>** In a Parallelogram ABCD , BC = 48 cm ,

AB = 25 cm and AE = 7 cm. And here we have to find the area of the given Parallelogram ABCD?

**<u>Explanation</u>****<u>:</u>****<u>-</u>**

In a Parallelogram ABCD ,

- BC = 48 cm
- AB = 25 cm
- AE = 7 cm

And

∆ AEB is a right angled triangle

Right angle at E

AB is the hypotenuse

We know that

By, Pythagoras theorem

Hypotenuse² = Side² + Side²

⇛ AB² = AE²+ BE²

⇛ 25² = 7² + BE²

⇛ 625 = 49 + BE²

⇛ BE² = 625-49

⇛ BE² = 576

⇛ BE = ±√576

⇛ BE = ±24

Since the length of the side cannot be <u>negative</u>

⇛ BE = 24 cm

⇛ BC = AD

⇛ AD = 48 cm

⇛ AE + ED = 48 cm

⇛ 7+ED = 48 cm

⇛ ED = 48-7

⇛ ED = 41 cm

We know that

Area of a Parallelogram = bh sq.units

Area of the given Parallelogram <u>ABCD</u>

⇛ AD × BE or BC × AE

⇛ 48 × 24 sq.cm

⇛ 1152 sq.cm

Therefore, the area of the given Parallelogram ABCD is 1152 sq.cm

**<em><u>Additional </u></em>****<em><u>comment:</u></em>**

Each side of the parallelogram is called its base.

Opposite sides are equal and parallel in a Parallelogram.

If you have any doubt, then you can ask me in the comments.

**Answer:**

A

**Step-by-step explanation:**

can you please mark me brainlest :D

**Answer:**

200

**Step-by-step explanation:**

Multiply the two.

.4 x 500 = 200