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Liula [17]
3 years ago
15

How to work it out now!!

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0
4) Use the formula for the area of a trapezium. Consider what the possible range of the various numbers might be, given their reported value, and how changes in value affect the area.

The area will be in the interval [445, 455) cm^2.
The length of the shorter parallel side will be in the interval [17.5, 18.5) cm.
The length of the longer parallel side will be in the interval [21.5, 22.5) cm.
The area is given by
.. A = (b1 +b2)/2*h
.. h = 2A/(b1 +b2)

h will get smaller when A gets smaller, so we want to do our calculation with the minimum value of A, 445 cm^2.
h will get smaller when b1 and b2 get larger, so we want to do our calculation with the maximum values of those numbers, 18.5 and 22.5 cm.

The minimum value of h will be
.. h = 2*(445 cm^2)/(18.5 cm +22.5 cm) = 21.7 cm


5. In the worst case, the lorry is limited to a load of
.. (14.5 -2.35)/(.255) = 47 . . . . crates

This is computed as the minimum safe additional load divided by the maximum mass per crate.
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mixer [17]
I don’t know what the question is, your just saying that
4 0
3 years ago
PLEASE HELP: The mass of a ball is 128 g. It has a density of 0.5 g/cm³. What is the volume of the ball? Show your work and plac
tiny-mole [99]

Answer:

Part 1) The volume of the ball is 256 cm³

Part 2) The radius of the ball is 3.94 cm

Step-by-step explanation:

Part 1) we know that

The density is equal to divide the mass by the volume

D=m/V

Solve for the volume

The volume is equal to divide the mass by the density

V=m/D

In this problem we have

m=128 g

D=0.5 g/cm³

substitute

V=128/0.5=256 cm³

Part 2) what is the radius of the ball?

we know that

The volume of the sphere (ball) is equal to

V=\frac{4}{3}\pi r^{3}

we have

V=256\ cm^{3}

assume

\pi =3.14

substitute and solve for r

256=\frac{4}{3}(3.14)r^{3}

768=(12.56)r^{3}

r^{3}=768/(12.56)

r=3.94\ cm

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=4x%20%5Csqrt%5B%20%2B%2015%20-%2015%5D%7B%3F%7D%20" id="TexFormula1" title="4x \sqrt[ + 15 - 1
blondinia [14]

Answer:

please what subject is this

6 0
3 years ago
The coordinate point F(-8, 0) after a dilation with scale factor of 0.25, centered at the origin, becomes the point
FrozenT [24]

Answer:

(-2,\, 0).

Step-by-step explanation:

Dilate a point (x,\, y) by a scale factor of r with (a,\, b) as the center, and the resultant point would be at (a + r\, (x - a),\, b + r\, (y - a)).

In this question:

Point to dilate: (x,\, y) = (-8,\, 0).

Scale factor: r = 0.25.

Center of dilation: (a,\, b) = (0,\, 0).

The resultant point would be:

(0 + 0.25\, (-8 - 0),\, 0 + 0.25\, (0 - 0)), which simplifies to (-2,\, 0).

5 0
3 years ago
If R is the midpoint of QS, QR= 8x-51 and RS = 3x-6, find QS.
sashaice [31]

QS would be 42. So the way i did it was I:

8x-51=3x-6

x=9

Plugged into both equations of QR and RS to then get the answer of 42

7 0
3 years ago
Read 2 more answers
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