2 years ago

Near a coral reef, a barracuda swam at a steady speed for 4.4seconds. It swam 33meters in that time. What was its speed?

Mathematics

1 answer:

PIT_PIT [208]2 years ago

3 0

Answer:

7.5 meters/second

Step-by-step explanation:

Speed = the magnitude of distance / time

Distance = 33 meters

Time = 4.4 seconds

Speed = 33 meters / 4.4 seconds = 7.5 meters/second. This is already to the tenths place, or the place right after the decimal, so we don't have to worry about rounding here.

You might be interested in

three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are

goldenfox [79]

We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure