Answer:
(A)A coordinate plane with a line starting at (negative 2, negative 4), passing through (0, negative 2) and (2, 1).
Step-by-step explanation:
Given the line: y=x-2
Comparing with the slope-intercept form y=mx+b
- Slope, m=1
- y-intercept is -2.
Therefore, the point (0,-2) must be on the line.
Only Options A and D have this point.
We then determine which has a slope, m=1.
<u>Option A</u>
Using points (-2,-4) and (0,-2)
Slope, ![m=\dfrac{-2-(-4)}{0-(-2)} =\dfrac{-2+4}{2}=1](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B-2-%28-4%29%7D%7B0-%28-2%29%7D%20%3D%5Cdfrac%7B-2%2B4%7D%7B2%7D%3D1)
<u>Option D</u>
Using points (-3,0) and (0,-2)
Slope, ![m=\dfrac{-2-0}{0-(-3)} =-\dfrac{2}{3}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B-2-0%7D%7B0-%28-3%29%7D%20%3D-%5Cdfrac%7B2%7D%7B3%7D)
Therefore, Option A satisfy the requirements.