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matrenka [14]
3 years ago
8

Kim got a "40" in a class and I make a 70 on a test. How much does the grade goes up?

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Answer:

30%

Step-by-step explanation:

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Factor the polynomial function over the complex numbers.
crimeas [40]

Answer:

Step-by-step explanation:

f(x)=x^4+3x^2-4

put x²=y

squaring x^4=y²

f(x)=y²+3y-4

=y²+4y-y-4

=y(y+4)-1(y+4)

=(y+4)(y-1)

so f(x)=(x²+4)(x²-1)

=[x²-(-4)](x²-1²)

=[x²-(4i²)](x²-1²)

=[x²-(2i)²](x²-1²)

=(x+2i)(x-2i)(x+1)(x-1)

[∵a²-b²=(a+b)(a-b)]

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3 years ago
What is the simplest form of 4a + 8b/12​<br> Step by step pls
shutvik [7]

Answer:

4a + 2b/3

Step-by-step explanation:

focus on 8b/12 first:

factor 8b/12 by 4 ---> 8b/12 = 4(2)b/4(3) ----> cancel 4 in the denominator and the nominator ---> 8b/12 = 4(2)b/4(3) = 2b/3

then, go back to 4a:

4a is in its simplest form, it can't be factor

therefore, plus 4a and 2b/3 = 4a + 2b/3

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3 years ago
What is m equal to if 7m+12/8=2m-1/3
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3 0
3 years ago
14. The area of a rectangle is 375 square inches and it’s perimeter is 80 inches. Find both the length and width.
Pavel [41]

Answer:

Length  =25 inches

Width = 15 inches

Step-by-step explanation:

Let l = length of rectangle, w = width of rectangle

Given the area and the perimeter of the rectangle, we can write:

lw = 375

2l+2w=80

So:

l+w = 80\div2

=40

l=40-w

Now, we can use substitution to find the value of w:

lw = 375

(40-w)w = 375

40w-w^2 = 375

375+w^2-40w = 0 (Quadratic equation)

(w-15)(w-25) = 0

∴ w = 15, 25

We can use substitution again to find the value of l

lw = 375

l=375\div w

=25,15

∵ Length usually refers to the longer side of a rectangle, ∴ length =25 inches and width =15 inches.

Hope this helps :)

8 0
3 years ago
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