Kim got a "40" in a class and I make a 70 on a test. How much does the grade goes up?

Write an equation in point-slope form for each line (If possible please show work)

Archy [21]

Answer: y-2=1/4(x-1)

Step-by-step explanation:

The formula for point-slope is y-y₁=m(x-x₁). Since we are given the slope m, we can fill that in. We are also given the point (x₁,y₁). We can also fill that in.

y-2=1/4(x-1)

8 0

3 years ago

Please help for 10 ponits

Vedmedyk [2.9K]

Answer:

it's a yes

Step-by-step explanation:

X/6 ≤ 30

to find the value of X we have to move the numerical to the other side

in this case the number is 1/6

X * 1/6 ≤ 30

so to balance the both side and get rid of the number on the left side we multiple with 6.

1/6*6 = 1 on the left side

30*6 = 180 on the right side

so the full equation will be

X * 1/6 * 6 ≤ 30 * 6

X * 1 ≤ 180

X ≤ 180

6 0

3 years ago

Read 2 more answers

PLS HELP WILL GIVE BRANLIEST In the first event, the eighth graders are running a baton relay race with three other classmates.

never [62]

Answer:

Total time = 56.81/60 + 59.22/60 + 57.39/60 + 60.11/60 = 3.89 minutes

Average Time in Minutes = 3.89 min / 4 = 0.97 minutes

Average Time in Seconds = 0.97 *60 = 58.38 Seconds

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Zoe spent $3200 for his new computer. The computer’s value will depreciate by 35% each year. How much will his computer be worth

vladimir1956 [14]

halo nino how are u doing today im the coocie man

6 0

3 years ago

A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po

astra-53 [7]

Answer:

a. See Attachment 1

b. $PT = 12.3\ m$

c. $HT = 31.1\ m$

d. $OH = 28.4\ m$

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OT}{20}$

Multiply both sides by 20

$20 * tan50 = \frac{OT}{20} * 20$

$20 * tan50 = OT$

$20 * 1.1918 = OT$

$23.836 = OT$

$OT = 23.836$

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

$tan30 = \frac{OP}{20}$

Multiply both sides by 20

$20 * tan30 = \frac{OP}{20} * 20$

$20 * tan30 = OP$

$20 * 0.5774= OP$

$11.548 = OP$

$OP = 11.548$

$PT = OT - OP$

$PT = 23.836 - 11.548$

$PT = 12.288$

$PT = 12.3\ m$ (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

$HT^2 = OT^2 + OH^2$

Substitute 20 for OH and $OT = 23.836$

$HT^2 = 20^2 + 23.836^2$

$HT^2 = 400 + 568.154896$

$HT^2 = 968.154896$

Take Square Root of both sides

$HT = \sqrt{968.154896}$

$HT = 31.1\ m$ <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OH}{OT}$

Multiply both sides by OT

$OT * tan50 = \frac{OH}{OT} * OT$

$OT * tan50 = {OH$

$OT * 1.1918 = OH$

Substitute $OT = 23.836$

$23.836 * 1.1918 = OH$

$28.4= OH$

$OH = 28.4\ m$ <em> (Approximated)</em>

5 0

3 years ago