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liberstina [14]
2 years ago
8

The military academy is placing cadets in rows for the parade. All rows must have the same number of cadets. If A company has 64

cadets and B company has 80 cadets, what is the greatest number of cadets who can be in each row?
Mathematics
2 answers:
serg [7]2 years ago
6 0

Answer:

the answer is 16 please make me brainliest :> thx uuu

scoray [572]2 years ago
4 0

Answer:

72

Step-by-step explanation:

If we find the average for both companies, it is 72, therefore there are two rows each with 72 cadets

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Answer 5, 6 , and 7 by today please.
kherson [118]

Answer:

Step-by-step explanation:

5. a) ∠1 and ∠2 are remote interior angles of ∠ACD so that means that ∠ACD = ∠1 + ∠2

   b) Because an exterior angle is the sum of its two remote interior angles it makes sense that an exterior angle is greater in measure than either of its remote interior angles.

6. BD = DB  Reflexive property

    ∠3 = ∠5, ∠4 = ∠6  Alt. int. angles

    ΔADB = ΔCDB   ASA

7. AB = BC Def. of midpoint

   ∠1 = ∠2 Given

   ∠BAE = ∠CBD Corresponding angles

   ΔBAE = ΔCBD ASA

    ∠D = ∠E CPCTC

3 0
2 years ago
PLEASEEE HELP ME WHAT IS THE ANSWER!!
blagie [28]

Answer:

Number 3 is correct.

129.19m

Step-by-step explanation:

You might be wondering how did I got 32⁰, well, that's because they are alternate angles.

Now, we're trying to find the opposite side of the triangle.

Using the laws,

we got cos32⁰=x/243.8

243.8cos32⁰=x

129.19⁰

Mark me as Brian list?

3 0
2 years ago
Find a polynomial that describes the area of the lawn which kevin has to mow in his front yard 6x+5,4x-9
Likurg_2 [28]

Answer:

Area=24x^2-34x-45

Step-by-step explanation:

Length and width of the yard are (6x+5) and (4x-9).

Area=length\times width\\\\Area=(6x+5)\times (4x-9)\\\\Area=24x^2+20x-54x-45\\\\Area=24x^2-34x-45

7 0
2 years ago
What point will y=2^x and y=3^x have in common?
mixas84 [53]
They both will have a y intercept of 0
6 0
3 years ago
Read 2 more answers
When a particular mass-spring system is started by stretching the spring 3 cm, one complete oscillation takes 4 seconds.
11Alexandr11 [23.1K]

Answer:

A. 5.16 s.

B. 5.66 s.

Step-by-step explanation:

A.

For a simple harmonic motion,

T = 2pi (sqrt * (l/g))

Given:

L1 = 3 cm

T1 = 4 s

L2 = 5 cm

T2 = ?

4 = 2pi*sqrt(3/g)

g = 7.4

At, L2,

T2 = 2pi*sqrt(5/7.4)

= 5.16 s.

B.

M1 = M1

M2 = 2*M1

For a simple harmonic motion,

T = 2pi (sqrt * (m/k))

4 = 2pi (sqrt * (M1/k))

M1/k = 0.405

Inputting the above values,

T2 = 2pi (sqrt * (2*M1/k))

= 2pi (sqrt * (2 * 0.405))

= 5.66 s.

4 0
2 years ago
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