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3 years ago

Which statement about the system of linear equations

Mathematics

2 answers:

zzz [600]3 years ago

8 0

Answer:

The lines have different slopes: first one is -2 and the second one is 0

There is one solution and it is (3, -3)

Step-by-step explanation:

liraira [26]3 years ago

4 0

Answer:

The lines have different slopes: first one is -2, the second is 0

There is one solution and it is (3, -3)

Step-by-step explanation:

straight line equation: ax + by + c = 0

slope m= -a/b

the first line has m = -2/1 = -2

the second has m = 0/1 = 0

to find the solution, if needed, simply consider the first equation and put -3 as value of y (the second equation gives you that value straight away y = -3)

so -3 = 2x -3

2x = -3 + 3 so 2x = 0 therefore x = 0

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The marginal loss on Washington reds, a brand of apples from the state of Washington, is $35 per case. The marginal profit is $1

AlexFokin [52]

Answer:

42666 cases

Step-by-step explanation:

P = (Marginal Loss)/ (Marginal Loss + Marginal Profit)

P = (35)/(35+15) = 0.7

Considering a normal distribution we can find the corresponding z value by P = 0.7 (which represented the shaded area under the curve)

z = 0.5244

z = (X - Mean Sales)/Standard Deviation

-0.5244 = (X - 45000)/4450

X = 42666.42 ≅ 42666

6 0

3 years ago

Ralph says he can rewrite (4+5)+21 as 9+21. Do you agree ?why or why not?

noname [10]

I agree because parentheses always go first and 4+5 equals 9 so in conclusion ralph is correct and the answer would be 30

4 0

3 years ago

Read 2 more answers

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Lady bird [3.3K]

Step-by-step explanation:

$\sqrt{3} is \: between1.7and1.8$

7 0

3 years ago

Is it true that an angle bisector is equidistant from the sides of the angle it is bisecting?

Viktor [21]

yes, if a point is on the bisector of an angle, then the point is outdistance

from sides of the angle

5 0

3 years ago

P(x) = x + 1x² – 34x + 343<br> d(x)= x + 9

Feliz [49]

Answer:

$x=\frac{9}{d-1},\:P=\frac{-297d+378}{\left(d-1\right)^2}+343$

Step-by-step explanation:

Let us start by isolating x for dx = x + 9.

dx - x = x + 9 - x > dx - x = 9.

Factor out the common term of x > x(d - 1) = 9.

Now divide both sides by d - 1 > $\frac{x\left(d-1\right)}{d-1}=\frac{9}{d-1};\quad \:d\ne \:1$ . Go ahead and simplify.

$x=\frac{9}{d-1};\quad \:d\ne \:1$ .

Now, $\mathrm{For\:}P=x+1x^2-34x+343, \mathrm{Subsititute\:}x=\frac{9}{d-1}$ .

$P=\frac{9}{d-1}+1\cdot \left(\frac{9}{d-1}\right)^2-34\cdot \frac{9}{d-1}+343$ .

Group the like terms... $1\cdot \left(\frac{9}{d-1}\right)^2+\frac{9}{d-1}-34\cdot \frac{9}{d-1}+343$ .

$\mathrm{Add\:similar\:elements:}\:\frac{9}{d-1}-34\cdot \frac{9}{d-1}=-33\cdot \frac{9}{d-1}$ > $1\cdot \left(\frac{9}{d-1}\right)^2-33\cdot \frac{9}{d-1}+343$ .

Now for $1\cdot \left(\frac{9}{d-1}\right)^2 > \mathrm{Apply\:exponent\:rule}: \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c} > \frac{9^2}{\left(d-1\right)^2} = 1\cdot \frac{9^2}{\left(d-1\right)^2}$ .

$\mathrm{Multiply:}\:1\cdot \frac{9^2}{\left(d-1\right)^2}=\frac{9^2}{\left(d-1\right)^2}$ .

Now for $33\cdot \frac{9}{d-1} > \mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} > \frac{9\cdot \:33}{d-1} > \frac{297}{d-1}$ .

Thus we then get $\frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}+343$ .

Now we want to combine fractions. $\frac{9^2}{\left(d-1\right)^2}-\frac{297}{d-1}$ .

$\mathrm{Compute\:an\:expression\:comprised\:of\:factors\:that\:appear\:either\:in\:}\left(d-1\right)^2\mathrm{\:or\:}d-1 > This\: is \:the\:LCM > \left(d-1\right)^2$

$\mathrm{For}\:\frac{297}{d-1}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:d-1 > \frac{297}{d-1}=\frac{297\left(d-1\right)}{\left(d-1\right)\left(d-1\right)}=\frac{297\left(d-1\right)}{\left(d-1\right)^2}$

$\frac{9^2}{\left(d-1\right)^2}-\frac{297\left(d-1\right)}{\left(d-1\right)^2} > \mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}> \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$\frac{9^2-297\left(d-1\right)}{\left(d-1\right)^2} > 9^2=81 > \frac{81-297\left(d-1\right)}{\left(d-1\right)^2}$ .

Expand $81-297\left(d-1\right) > -297\left(d-1\right) > \mathrm{Apply\:the\:distributive\:law}: \:a\left(b-c\right)=ab-ac$ .

$-297d-\left(-297\right)\cdot \:1 > \mathrm{Apply\:minus-plus\:rules} > -\left(-a\right)=a > -297d+297\cdot \:1$ .

$\mathrm{Multiply\:the\:numbers:}\:297\cdot \:1=297 > -297d+297 > 81-297d+297 > \mathrm{Add\:the\:numbers:}\:81+297=378 > -297d+378 > \frac{-297d+378}{\left(d-1\right)^2}$

Therefore $P=\frac{-297d+378}{\left(d-1\right)^2}+343$ .

Hope this helps!

5 0

4 years ago