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Rom4ik [11]
3 years ago
5

Can u help me with this

Mathematics
2 answers:
erica [24]3 years ago
8 0
The last one because it can be traced like Jerome gets these cards from this place but others from a different place
SOVA2 [1]3 years ago
7 0
How many cards does Jerome have altogether is the answer because the total number of cards is a statistic 

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At the sewing store ashly bought a bag of mixed buttons she got 25 buttons in all 5 of the buttons were large what percentage of
iren [92.7K]

Answer:

20%

Step-by-step explanation:

You have to do 5/25, giving you 20%.

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Please help asap !! : (((((
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Answer: it is 65%

Step-by-step explanation:

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3 years ago
Mike bought five items for lunch that Cost a total of 4.55 .Hit dogs cost .1.10 each and cookies cost 0.75 each. What equation c
-Dominant- [34]

Answer:

c + h = 5 and

0.75c + 1.10h = 4.55

Step-by-step explanation:

Assume that Mike bought only cookies and hot dogs.

The total can be represented as:

Cookies + Hot\ Dogs = 5 --- (1)

And the amount spent can be represented as:

Cost\ of\ cookies + Cost\ of\ hot\ dogs = 4.55 --- (2)

Required

Determine the system of equation

Let c represents the number of cookies and h, number of hot dogs.

Cookies + Hot\ Dogs = 5 implies c + h = 5

And

Cost\ of\ cookies + Cost\ of\ hot\ dogs = 4.55

Cost of cookies = 0.75 * c

Cost of hot dogs = 1.10 * h

So, we have:

0.75c + 1.10h = 4.55

Hence, the equations are:

c + h = 5 and

0.75c + 1.10h = 4.55

Solving for c and h

Make c the subject in c + h = 5

c = 5 - h

Substitute 5 - h for c in 0.75c + 1.10h = 4.55

0.75(5- h) + 1.10h = 4.55

3.75- 0.75h + 1.10h = 4.55

3.75 +0.35h = 4.55

Collect Like Terms

0.35h = 4.55 - 3.75

0.35h = 0.8

Solve for h

h = 0.8/0.35

h = 2.28571428571

h =2 -- approximated

Recall that:

c = 5 - h

c = 5 - 2

c =3

5 0
3 years ago
Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th
Sloan [31]

Answer:  3x^2y\sqrt[3]{y}\\\\

Work Shown:

\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

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Write down two factors of 18
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Any two factors of 18 2 ,3

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