Answer:
a. The possible dimensions of the total area are;
The width of the total area is (2·x + 8) inches
The length of the total area is (2·x + 10) inches
b. The dimensions of the photos are as follows;
The length of the photos are 10 inches
The width of the photos are 8 inches
Step-by-step explanation:
a. Given that the area, A = 4·x² + 36·x + 80
We get;
A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)
Therefore, the possible dimensions of the total area (photo + mat) are;
The width of the total area (photo + mat) = (2·x + 8) in.
The length of the total area (photo + mat) = (2·x + 10) in.
b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each
Therefore, we have the dimensions of the photos are as follows;
The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.
The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.
Answer:
3/2
Step-by-step explanation:
Each of the toppings cost 2$
Answer:
P ($1 or $5) = 5/6
Step-by-step explanation:
There are 6 $1
There are 4 $5
There are 2 $10
There are a total of 12 spaces
P ($1 or $5) = ($1 or $5)/ total
There are 6 ones and 4 fives
= (6+4)/ 12
= 10/12
Divide the top and bottom by 2
=5/6
Calculating could be confusing and leading to an incorrect answer.
